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प्रश्न
Arrange the following compounds in decreasing order of acidity.
\[\ce{H2O, ROH, HC ≡ CH}\]
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उत्तर
The decreasing order of the acidity of the given compounds:
\[\ce{H2O > ROH > HC ≡ CH}\]
\[\ce{HC ≡ CH}\] is less acidic because the carbon atoms here is sp hybridized, so the electron density is higher on the carbon atom.
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संबंधित प्रश्न
Name the following compound according to the IUPAC system.
\[\begin{array}{cc}
\phantom{.....................................}\ce{CH2OH}\\
\phantom{............................}|\\
\ce{CH3 - CH - CH2 - CH - CH - CH3}\\
|\phantom{....................}|\phantom{............}\\
\ce{CH3}\phantom{..............}\ce{OH}\phantom{.........}\\
\end{array}\]
Name the following compound according to the IUPAC system.
\[\begin{array}{cc}
\ce{CH3 - C = C - CH2OH}\\
|\phantom{......}|\phantom{.....}\\
\ce{CH3}\phantom{.}\ce{Br}\phantom{....}\\
\end{array}\]
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\[\begin{array}{cc}
\ce{CH3-CH-OCH3}\\
|\phantom{....}\\
\ce{CH3}\phantom{..}
\end{array}\]
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\[\begin{array}{cc}
\phantom{...............}\ce{CH3}\\
\phantom{.............}|\\
\ce{CH3 - CH - CH - C - CH3}\\
|\phantom{......}|\phantom{......}|\\
\phantom{...}\ce{CH3}\phantom{..}\ce{OH}\phantom{...}\ce{CH3}
\end{array}\]
