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प्रश्न
What happens when benzene diazonium chloride is heated with water?
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उत्तर
When benzene diazonium chloride is heated with water, it forms phenol along with nitrogen and hydrochloric acid as by-products as shown below:

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संबंधित प्रश्न
Write IUPAC name of the following compound:
C6H5 – O – C7H15(n−)
Write IUPAC name of the following compound:
\[\begin{array}{cc}
\ce{CH3 - CH2 - O - CH - CH2 - CH3}\\
\phantom{...}|\\
\phantom{.....}\ce{CH3}
\end{array}\]
Give IUPAC name of the following ether:
O2N – C6H4 – OCH3(p)
Ethylidene dichloride when boiled with aqueous solution of NaOH yields _______.
(A) formaldehyde
(B) acetaldehyde
(C) acetone
(D) ethyl methyl ketone
Write the IUPAC name of the following :

Write IUPAC names of the following

Isopropyl alcohol on oxidation forms:
3-methylphenol is called ____________.
An example of a compound with functional group – O – is ____________.
Ethylene reacts with Baeyer’s reagent to give ______.
The product of acid catalysed hydration of 2-phenylpropene is:
Which of the following gives a positive iodoform test?
The correct acidic strength order of the following is:

(I)

(II)

(III)
IUPAC name of m-cresol is ______.
Arrange the following compounds in decreasing order of acidity.
\[\ce{H2O, ROH, HC ≡ CH}\]
Assertion: IUPAC name of the compound
\[\begin{array}{cc}
\ce{CH3 - CH - O - CH2 - CH2 - CH3}\\
|\phantom{....................}\\
\ce{CH3}\phantom{.................}
\end{array}\] is 2-Ethoxy-2-methylethane.
Reason: In IUPAC nomenclature, ether is regarded as hydrocarbon derivative in which a hydrogen atom is replaced by —OR or —OAr group [where R = alkyl group and Ar = aryl group]
Write complete reaction for the bromination of phenol in aqueous and non-aqueous medium.
Explain why Lewis acid is not required in bromination of phenol?
The IUPAC name of
is ______.
Write IUPAC name of the following compound:
\[\begin{array}{cc}
\phantom{................}\ce{CH3}\\
\phantom{.............}|\\
\ce{CH3 - CH - CH - C - CH3}\\
|\phantom{......}|\phantom{......}|\\
\phantom{...}\ce{CH3}\phantom{...}\ce{OH}\phantom{...}\ce{CH3}
\end{array}\]
