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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Arrange the following compounds in decreasing order of acidity. HX2O,ROH,HC ≡ CH

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प्रश्न

Arrange the following compounds in decreasing order of acidity.

\[\ce{H2O, ROH, HC ≡ CH}\]

टीपा लिहा
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उत्तर

The decreasing order of the acidity of the given compounds:

\[\ce{H2O > ROH > HC ≡ CH}\]

\[\ce{HC ≡ CH}\] is less acidic because the carbon atoms here is sp hybridized, so the electron density is higher on the carbon atom.

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पाठ 11: Alcohols, Phenols and Ethers - Multiple Choice Questions (Type - I) [पृष्ठ १५९]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 12
पाठ 11 Alcohols, Phenols and Ethers
Multiple Choice Questions (Type - I) | Q 37 | पृष्ठ १५९

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\ce{CH3 - C = C - CH2OH}\\
|\phantom{......}|\phantom{.....}\\
\ce{CH3}\phantom{.}\ce{Br}\phantom{....}\\
\end{array}\]


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\phantom{................}\ce{CH3}\\
\phantom{.............}|\\
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|\phantom{......}|\phantom{......}|\\
\phantom{...}\ce{CH3}\phantom{..}\ce{OH}\phantom{...}\ce{CH3}
\end{array}\]


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\[\begin{array}{cc}
\phantom{................}\ce{CH3}\\
\phantom{.............}|\\
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\phantom{.}|\phantom{......}|\phantom{......}|\\
\phantom{....}\ce{CH3\phantom{...}\ce{OH}\phantom{...}\ce{CH3}}\
\end{array}\]


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