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प्रश्न
Arrange the following compounds in decreasing order of acidity.
\[\ce{H2O, ROH, HC ≡ CH}\]
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उत्तर
The decreasing order of the acidity of the given compounds:
\[\ce{H2O > ROH > HC ≡ CH}\]
\[\ce{HC ≡ CH}\] is less acidic because the carbon atoms here is sp hybridized, so the electron density is higher on the carbon atom.
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संबंधित प्रश्न
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\[\begin{array}{cc}
\phantom{................}\ce{CH3}\\
\phantom{.............}|\\
\ce{CH3 - CH - CH - C - CH3}\\
|\phantom{......}|\phantom{......}|\\
\phantom{...}\ce{CH3\phantom{.}}\phantom{..}\ce{OH}\phantom{...}\ce{CH3}
\end{array}\]
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\phantom{...}|\\
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\end{array}\]
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\[\begin{array}{cc}
\phantom{................}\ce{CH3}\\
\phantom{.............}|\\
\ce{CH3 - CH - CH - C -CH3}\\
\phantom{.}|\phantom{......}|\phantom{......}|\\
\phantom{....}\ce{CH3\phantom{...}\ce{OH}\phantom{...}\ce{CH3}}\
\end{array}\]
