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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Arrange the following compounds in decreasing order of acidity. HX2O,ROH,HC ≡ CH

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प्रश्न

Arrange the following compounds in decreasing order of acidity.

\[\ce{H2O, ROH, HC ≡ CH}\]

टीपा लिहा
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उत्तर

The decreasing order of the acidity of the given compounds:

\[\ce{H2O > ROH > HC ≡ CH}\]

\[\ce{HC ≡ CH}\] is less acidic because the carbon atoms here is sp hybridized, so the electron density is higher on the carbon atom.

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पाठ 11: Alcohols, Phenols and Ethers - Multiple Choice Questions (Type - I) [पृष्ठ १५९]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 12
पाठ 11 Alcohols, Phenols and Ethers
Multiple Choice Questions (Type - I) | Q 37 | पृष्ठ १५९

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\[\begin{array}{cc}
\phantom{.....................................}\ce{CH2OH}\\
\phantom{............................}|\\
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|\phantom{....................}|\phantom{............}\\
\ce{CH3}\phantom{..............}\ce{OH}\phantom{.........}\\
\end{array}\]


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|\phantom{......}|\phantom{.....}\\
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\end{array}\]


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\[\begin{array}{cc}
\phantom{................}\ce{CH3}\\
\phantom{.............}|\\
\ce{CH3 - CH - CH - C  -CH3}\\
\phantom{.}|\phantom{......}|\phantom{......}|\\
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\end{array}\]


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\[\begin{array}{cc}
\phantom{................}\ce{CH3}\\
\phantom{.............}|\\
\ce{CH3 - CH - CH - C - CH3}\\
|\phantom{......}|\phantom{......}|\\
\phantom{...}\ce{CH3}\phantom{...}\ce{OH}\phantom{...}\ce{CH3}
\end{array}\]


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