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प्रश्न
Give reasons Fluoride ion has higher hydration enthalpy than chloride ion.
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उत्तर
Fluoride ion is smaller in size than the chloride ion. Hence, when the two are dissolved in water, the energy of hydration released in the case of fluoride ion will be more than chloride ion due to stronger interactions (ion-dipole) between the ion and the water molecules in the former. Fluorine being more electronegative than chlorine will form stronger H-bonds with hydrogen present in the water molecule.
`triangleH_("hyd")F^(-) > triangle H_("hyd") Cl^(-)`
संबंधित प्रश्न
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\[\begin{array}{cc}
\ce{CH3 - O - CH2 - CH - CH3}\\
\phantom{................}|\\
\phantom{....................}\ce{CH3}
\end{array}\]
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| Column I | Column II | ||
| (i) | CH3—O—CH3 | (a) |  |
| (ii) | \[\begin{array}{cc} \ce{CH3}\phantom{..................}\\ \backslash\phantom{.............}\\ \ce{CH-O-CH3}\\ /\phantom{..............}\\ \ce{CH3}\phantom{..................} \end{array}\] |
(b) | \[\begin{array}{cc} \ce{CH3}\phantom{....}\\ |\phantom{.......}\\ \ce{CH3-C-I + CH3OH}\\ |\phantom{.......}\\ \ce{CH3}\phantom{....} \end{array}\] |
| (iii) | \[\begin{array}{cc} \ce{CH3}\phantom{.}\\ |\phantom{....}\\ \ce{H3C-C-O-CH3}\\ |\phantom{....}\\ \ce{CH3}\phantom{..} \end{array}\] |
(c) |  |
| (iv) |  |
(d) | CH3—OH + CH3—I |
| (e) | \[\begin{array}{cc} \ce{CH3}\phantom{.....................}\\ \backslash\phantom{.................}\\ \ce{CH-OH + CH3I}\\ /\phantom{.................}\\ \ce{CH3}\phantom{.....................} \end{array}\] |
||
| (f) | \[\begin{array}{cc} \ce{CH3}\phantom{.....................}\\ \backslash\phantom{.................}\\ \ce{CH-I + CH3OH}\\ /\phantom{.................}\\ \ce{CH3}\phantom{.....................} \end{array}\] |
||
| (g) | \[\begin{array}{cc} \ce{CH3}\phantom{....}\\ |\phantom{.......}\\ \ce{CH3-C-OH + CH3I}\\ |\phantom{.......}\\ \ce{CH3}\phantom{....} \end{array}\] |
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