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प्रश्न
Give reasons Although –NH2 is o/p directing group, yet aniline on nitration gives a significant amount of m-nitroaniline
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उत्तर
Nitration is usually carried out with a mixture of concentrated HNO3 and concentrated H2SO4. In the presence of these acids, most of aniline gets protonated to form anilinium ion. Therefore, in presence of acids, the reaction mixture consists of aniline and anilinium ion. Nitration of aniline due to steric hindrance at ortho position, mainly gives para nitroaniline and the nitration of anilinium ion gives m-nitroaniline. In actual practice, approximately 1:1 mixture of p-nitroaniline: m-nitroaniline is obtained.
Thus, nitration of aniline gives a substantial amount of m-nitroaniline due to protonation of the amino group.
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संबंधित प्रश्न
Write the IUPAC name of the following compound and classify it as primary, secondary and tertiary amine.
m−BrC6H4NH2
Account for the following:
pKb of aniline is more than that of methylamine.
How will you convert ethanoic acid into methanamine?
Complete the following reaction:
\[\ce{C6H5NH2 + Br2 (aq) ->}\]
Complete the following reaction:
\[\ce{C6H5NH2 + (CH3CO)2O ->}\]
Do the following conversions in not more than two steps :
Ethyl benzene to Benzoic acid
What is the action of p-toluenesulphonychloride on ethylamine and diethylamine?
Identify the incorrect IUPAC name.
Do the following conversions in not more than two steps:
\[\begin{array}{cc}
\ce{CH3CN to CH3 - C - CH3}\\
\phantom{...........}||\\
\phantom{...........}\ce{O}
\end{array}\]
Do the following conversions in not more than two steps:
