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प्रश्न
Account for the following:
Methylamine in water reacts with ferric chloride to precipitate hydrated ferric oxide.
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उत्तर
Due to the +I effect of −CH3 group, methylamine is more basic than water. Therefore, in water, methylamine produces OH− ions by accepting H+ ions from water.
\[\ce{CH3-NH2 + H-OH -> H3N+-CH3 + OH-}\]
Ferric chloride (FeCl3) dissociates in water to form Fe3+ and Cl− ions.
Then, OH− ion reacts with Fe3+ ion to form a precipitate of hydrated ferric oxide.
\[\ce{FeCl3 -> Fe^{3+} + 3Cl^-}\]
\[\ce{2Fe^{3+} + 6OH^- -> \underset{(Brown precipitate)}{Fe2O3.3H2O}}\]
संबंधित प्रश्न
Which among the following molecular formulae represents urotropine?
(a) C6H12N4
(b) C6H24H4
(c) C6H12N4O2
(d) C6H24N4O2
Convert 3-Methylaniline into 3-nitrotoluene.
Write the IUPAC name of the following compound and classify it as primary, secondary and tertiary amine.
C6H5NHCH3
Give one chemical test to distinguish between the following pair of compounds.
Methylamine and dimethylamine
Give one chemical test to distinguish between the following pair of compounds.
Secondary and tertiary amines
Give one chemical test to distinguish between the following pair of compounds.
Ethylamine and aniline
How will you convert ethanoic acid into methanamine?
How will you convert nitromethane into dimethylamine?
How will you convert propanoic acid into ethanoic acid?
Accomplish the following conversion:
Benzoic acid to aniline
Accomplish the following conversion:
Aniline to 2, 4, 6-tribromofluorobenzene
An aromatic compound ‘A’ on treatment with aqueous ammonia and heating forms compound ‘B’ which on heating with Br2 and KOH forms a compound ‘C’ of molecular formula C6H7N. Write the structures and IUPAC names of compounds A, B and C.
Do the following conversions in not more than two steps :
Ethyl benzene to Benzoic acid
Write the IUPAC name of the given compound :
Give simple chemical tests to distinguish between the following pair of compounds:
Benzaldehyde and Benzoic acid
Using IUPAC norms, write the formula of Hexaamminecobalt(III) sulphate.
An organic compound (A) with molecular formula C3H7NO on heating with Br2 and KOH forms a compound (B). Compound (B) on heating with CHCl3 and alcoholic KOH produces a foul-smelling compound (C) and on reacting with C6H5SO2Cl forms a compound (D) which is soluble in alkali. Write the structure of (A), (B), (C) and (D).
Predict the product 'A' in the following reaction.
\[\ce{\underset{(Acetyl chloride)}{CH3COCl}->[H2][Pd-BaSO4]A + HCl}\]
