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Question
Account for the following:
Methylamine in water reacts with ferric chloride to precipitate hydrated ferric oxide.
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Solution
Due to the +I effect of −CH3 group, methylamine is more basic than water. Therefore, in water, methylamine produces OH− ions by accepting H+ ions from water.
\[\ce{CH3-NH2 + H-OH -> H3N+-CH3 + OH-}\]
Ferric chloride (FeCl3) dissociates in water to form Fe3+ and Cl− ions.
Then, OH− ion reacts with Fe3+ ion to form a precipitate of hydrated ferric oxide.
\[\ce{FeCl3 -> Fe^{3+} + 3Cl^-}\]
\[\ce{2Fe^{3+} + 6OH^- -> \underset{(Brown precipitate)}{Fe2O3.3H2O}}\]
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\[\begin{array}{cc}
\ce{CH3CN to CH3 - C - CH3}\\
\phantom{...........}||\\
\phantom{...........}\ce{O}
\end{array}\]
