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प्रश्न
Account for the following:
Although the amino group is o, p-directing in aromatic electrophilic substitution reactions, aniline on nitration gives a substantial amount of m-nitroaniline.
Give reasons for the following:
Although the –NH2 group is o/p directing in an electrophilic substitution reaction, yet aniline on nitration gives a good yield of m-nitroaniline.
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उत्तर १
Nitration is carried out in an acidic medium. In an acidic medium, aniline is protonated to give anilinium ions (which are meta-directing).

For this reason, aniline on nitration gives a substantial amount of m-nitroaniline.
उत्तर २
Nitration is usually carried out with a mixture of conc. HNO3 + conc. H2SO4. In the presence of these acids, most of the aniline gets protonated to form an anilinium ion. Therefore, in the presence of acids, the reaction mixture consists of aniline and anilinium ions. Now, the –NH2 group in aniline is activating and p-directing, while the \[\ce{-NH+3}\] group in the anilinium ion is deactivating and m-directing. Nitration of aniline (due to steric hindrance at the o-position) mainly gives p-nitroaniline; the nitration of anilinium ions gives m-nitroaniline. In actual practice, approx. a 1 : 1 mixture of p-nitroaniline and m-nitroaniline is obtained. Thus, nitration of aniline gives a substantial amount of m-nitroaniline due to protonation of the amino group.

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संबंधित प्रश्न
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Aniline is acetylated before nitration reaction.
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Aniline does not react with methyl chloride in the presence of anhydrous AlCl3 catalyst.
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Statement II: Aniline cannot be prepared through Gabriel synthesis.
In the light of the above statements, choose the correct answer from the options given below:
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\[\ce{CH3 - CH2 - CH2 - I ->[NaCN] A ->[OH-][Partial hydrolysis] B ->[NaOH][Br2] \underset{(major)}{C}}\]
