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प्रश्न
How is chlorobenzene prepared from aniline?
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उत्तर
Aniline reacts with nitrous acid to give benzene diazonium chloride which on treatment with cuprous chloride gives chlorobenzene
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संबंधित प्रश्न
What is the action of acetic anhydride on ethylamine?
What is the action of the following reagents on aniline?
Bromine water
Write the structures of main products when aniline reacts with the following reagents :
Br2 water
Write the structures of main products when aniline reacts with the following reagents :
(CH3CO)2O/pyridine
Account for the following:
Although the amino group is o, p-directing in aromatic electrophilic substitution reactions, aniline on nitration gives a substantial amount of m-nitroaniline.
Write short notes on acetylation.
What is the action of acetic anhydride on diethylamine?
What is the action of the following reagents on aniline?
Acetic anhydride
What is the action of the following reagents on aniline?
Hot and conc. sulphuric acid
Illustrate the following reactions giving suitable example in each case
Acetylation of amines
How will you convert the following?
Aniline into N−phenylethanamide
What is the role of \[\ce{HNO3}\] in the nitrating mixture used for nitration of benzene?
A solution contains 1 g mol. each of p-toluene diazonium chloride and p-nitrophenyl diazonium chloride. To this 1 g mol. of alkaline solution of phenol is added. Predict the major product. Explain your answer.
Assertion: N, N-Diethylbenzene sulphonamide is insoluble in alkali.
Reason: Sulphonyl group attached to nitrogen atom is strong electron-withdrawing group.
When bromination of aniline is carried out by protecting – NH2. The major product is
Give reasons for the following observation:
Aniline is acetylated before nitration reaction.
Given below are two statements:
Statement I: Aniline does not undergo a Friedel-Crafts alkylation reaction.
Statement II: Aniline cannot be prepared through Gabriel synthesis.
In the light of the above statements, choose the correct answer from the options given below:
Identify the major product C formed in the following reaction sequence:
\[\ce{CH3 - CH2 - CH2 - I ->[NaCN] A ->[OH-][Partial hydrolysis] B ->[NaOH][Br2] \underset{(major)}{C}}\]
