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प्रश्न
How is chlorobenzene prepared from aniline?
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उत्तर
Aniline reacts with nitrous acid to give benzene diazonium chloride which on treatment with cuprous chloride gives chlorobenzene
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संबंधित प्रश्न
What is the action of acetic anhydride on ethylamine?
Give reasons for the following:
Aniline does not undergo Friedel- Crafts reaction.
Write the structures of main products when aniline reacts with the following reagents :
Br2 water
Write the structures of main products when aniline reacts with the following reagents :
(CH3CO)2O/pyridine
What is the action of acetic anhydride on diethylamine?
What is the action of the following reagents on aniline?
Hot and conc. sulphuric acid
Illustrate the following reactions giving suitable example in each case
Acetylation of amines
How will you convert the following?
Aniline into N−phenylethanamide
In the nitration of benzene using a mixture of conc. \[\ce{H2SO4}\] and conc. \[\ce{HNO3}\], the species which initiates the reaction is ______.
What is the role of \[\ce{HNO3}\] in the nitrating mixture used for nitration of benzene?
A solution contains 1 g mol. each of p-toluene diazonium chloride and p-nitrophenyl diazonium chloride. To this 1 g mol. of alkaline solution of phenol is added. Predict the major product. Explain your answer.
Assertion: N, N-Diethylbenzene sulphonamide is insoluble in alkali.
Reason: Sulphonyl group attached to nitrogen atom is strong electron-withdrawing group.
When bromination of aniline is carried out by protecting – NH2. The major product is
Give reasons for the following observation:
Aniline is acetylated before nitration reaction.
Give reasons for the following observation:
Aniline does not react with methyl chloride in the presence of anhydrous AlCl3 catalyst.
In the following reaction, the reason for why meta-nitro product also formed is:
How can the activating effect of the −NH2 group in aniline be controlled?
Aniline does not give Friedel-Crafts reaction. Give a reason.
Given below are two statements:
Statement I: Aniline does not undergo a Friedel-Crafts alkylation reaction.
Statement II: Aniline cannot be prepared through Gabriel synthesis.
In the light of the above statements, choose the correct answer from the options given below:
Identify the major product C formed in the following reaction sequence:
\[\ce{CH3 - CH2 - CH2 - I ->[NaCN] A ->[OH-][Partial hydrolysis] B ->[NaOH][Br2] \underset{(major)}{C}}\]
