Advertisements
Advertisements
प्रश्न
What is the role of \[\ce{HNO3}\] in the nitrating mixture used for nitration of benzene?
Advertisements
उत्तर
\[\ce{HNO3}\] acts as a base in the nitrating mixture \[\ce{(HNO3 + H2SO4)}\] and provides the electrophile.
\[\ce{HNO3 + H2SO4 -> \underset{Electrophile}{NO^{+}2 + HSO^{-}4} + H2O}\]
APPEARS IN
संबंधित प्रश्न
How is chlorobenzene prepared from aniline?
What is the action of the following reagents on aniline?
Bromine water
Give reasons for the following:
Aniline does not undergo Friedel- Crafts reaction.
Write the structures of main products when aniline reacts with the following reagents :
Br2 water
Write the chemical equations involved when aniline is treated with the following reagents:
Br2 water
Account for the following:
Although the amino group is o, p-directing in aromatic electrophilic substitution reactions, aniline on nitration gives a substantial amount of m-nitroaniline.
Write short notes on acetylation.
Illustrate the following reactions giving suitable example in each case
Acetylation of amines
How will you convert the following?
Aniline into N−phenylethanamide
Assertion: N, N-Diethylbenzene sulphonamide is insoluble in alkali.
Reason: Sulphonyl group attached to nitrogen atom is strong electron-withdrawing group.
How can the activating effect of the −NH2 group in aniline be controlled?
Assertion (A): Bromination of benzoic acid, gives m-bromobenzoic acid.
Reason (R): Carboxyl group increases the electron density at the meta position.
Aniline does not give Friedel-Crafts reaction. Give a reason.
Given below are two statements:
Statement I: Aniline does not undergo a Friedel-Crafts alkylation reaction.
Statement II: Aniline cannot be prepared through Gabriel synthesis.
In the light of the above statements, choose the correct answer from the options given below:
Identify the major product C formed in the following reaction sequence:
\[\ce{CH3 - CH2 - CH2 - I ->[NaCN] A ->[OH-][Partial hydrolysis] B ->[NaOH][Br2] \underset{(major)}{C}}\]
