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What is the role of HNOX3 in the nitrating mixture used for nitration of benzene? - Chemistry

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प्रश्न

What is the role of \[\ce{HNO3}\] in the nitrating mixture used for nitration of benzene?

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उत्तर

\[\ce{HNO3}\] acts as a base in the nitrating mixture \[\ce{(HNO3 + H2SO4)}\] and provides the electrophile.

\[\ce{HNO3 + H2SO4 -> \underset{Electrophile}{NO^{+}2 + HSO^{-}4} + H2O}\]

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पाठ 13: Amines - Multiple Choice Questions (Type - I) [पृष्ठ १८८]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 12
पाठ 13 Amines
Multiple Choice Questions (Type - I) | Q 38 | पृष्ठ १८८

संबंधित प्रश्‍न

How is chlorobenzene prepared from aniline?


What is the action of acetic anhydride on ethylamine?


Write the structures of main products when aniline reacts with the following reagents :

Br2 water


Write the structures of main products when aniline reacts with the following reagents :

(CH3CO)2O/pyridine


Write the chemical equations involved when aniline is treated with the following reagents:

Br2 water


Write short notes on acetylation.


What is the action of the following reagents on aniline?

Acetic anhydride

 


What is the action of the following reagents on aniline?

Hot and conc. sulphuric acid


Illustrate the following reactions giving suitable example in each case 

Acetylation of amines


Assertion: N, N-Diethylbenzene sulphonamide is insoluble in alkali.

Reason: Sulphonyl group attached to nitrogen atom is strong electron-withdrawing group.


When bromination of aniline is carried out by protecting – NH2. The major product is


Give reasons for the following observation:

Aniline does not react with methyl chloride in the presence of anhydrous AlCl3 catalyst.


In the following reaction, the reason for why meta-nitro product also formed is:


How can the activating effect of the −NH2 group in aniline be controlled?


Assertion (A): Bromination of benzoic acid, gives m-bromobenzoic acid.

Reason (R): Carboxyl group increases the electron density at the meta position.


Given below are two statements:

Statement I: Aniline does not undergo a Friedel-Crafts alkylation reaction.

Statement II: Aniline cannot be prepared through Gabriel synthesis.

In the light of the above statements, choose the correct answer from the options given below:


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