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प्रश्न
Assertion: N, N-Diethylbenzene sulphonamide is insoluble in alkali.
Reason: Sulphonyl group attached to nitrogen atom is strong electron-withdrawing group.
पर्याय
Both assertion and reason are wrong.
Both assertion and reason are correct statements but reason is not correct explanation of assertion.
Assertion is correct statement but reason is wrong statement.
Both assertion and reason are correct statements and reason is correct explanation of assertion.
Assertion is wrong statement but reason is correct statement.
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उत्तर
Both assertion and reason are correct statements but reason is not correct explanation of assertion.
Explanation:
N, N-diethyl benzene sulphonamide is insoluble in alkali because it has no acidic hydrogen. Sulphonyl group attached to nitrogen atom is electron-withdrawing group.
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संबंधित प्रश्न
How is chlorobenzene prepared from aniline?
What is the action of acetic anhydride on ethylamine?
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Aniline does not undergo Friedel- Crafts reaction.
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Br2 water
Write the structures of main products when aniline reacts with the following reagents :
(CH3CO)2O/pyridine
Write the chemical equations involved when aniline is treated with the following reagents:
Br2 water
Write short notes on acetylation.
What is the action of the following reagents on aniline?
Acetic anhydride
What is the action of the following reagents on aniline?
Hot and conc. sulphuric acid
How will you convert the following?
Aniline into N−phenylethanamide
In the nitration of benzene using a mixture of conc. \[\ce{H2SO4}\] and conc. \[\ce{HNO3}\], the species which initiates the reaction is ______.
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When bromination of aniline is carried out by protecting – NH2. The major product is
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Aniline is acetylated before nitration reaction.
How can the activating effect of the −NH2 group in aniline be controlled?
Assertion (A): Bromination of benzoic acid, gives m-bromobenzoic acid.
Reason (R): Carboxyl group increases the electron density at the meta position.
Identify the major product C formed in the following reaction sequence:
\[\ce{CH3 - CH2 - CH2 - I ->[NaCN] A ->[OH-][Partial hydrolysis] B ->[NaOH][Br2] \underset{(major)}{C}}\]
