मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Give reasons for the following: Aniline does not undergo Friedel- Crafts reaction.

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प्रश्न

Give reasons for the following:

Aniline does not undergo Friedel- Crafts reaction.

Account for the following:

Aniline does not undergo Friedel-Crafts reaction.

Why aniline does not undergo Friedel-Crafts reaction?

रासायनिक समीकरणे/रचना
कारण सांगा
लघु उत्तर
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उत्तर १

A Friedel-Crafts reaction is carried out in the presence of AlCl3. But AlCl3 is acidic in nature, while aniline is a strong base. Thus, aniline reacts with AlCl3 to form a salt (as shown in the following equation).


Due to the positive charge on the N-atom, electrophilic substitution in the benzene ring is deactivated. Hence, aniline does not undergo the Friedel-Crafts reaction.

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उत्तर २

The Friedel-Crafts reaction is an electrophilic substitution reaction that occurs in the presence of aluminium chloride (AlCl3) as a catalyst. AlCl3 acts as a Lewis acid, while aniline is a base. Therefore, their reaction forms a salt:

\[\ce{C6H5NH2 + AlCl3 -> \underset{(Salt)}{C6H5NH^+_2AlCl^-_3}}\]

Due to the decrease in electron density on the nitrogen atom, this salt deactivates the benzene ring towards further reaction. As a result, aniline does not undergo the Friedel-Crafts reaction.

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 9: Amines - Exercises [पृष्ठ २७८]

संबंधित प्रश्‍न

How is chlorobenzene prepared from aniline?


What is the action of acetic anhydride on ethylamine?


Write the structures of main products when aniline reacts with the following reagents :

Br2 water


Write the chemical equations involved when aniline is treated with the following reagents:

Br2 water


Account for the following:

Although the amino group is o, p-directing in aromatic electrophilic substitution reactions, aniline on nitration gives a substantial amount of m-nitroaniline.


Illustrate the following reactions giving suitable example in each case 

Acetylation of amines


How will you convert the following?

Aniline into N−phenylethanamide


In the nitration of benzene using a mixture of conc. \[\ce{H2SO4}\] and conc. \[\ce{HNO3}\], the species which initiates the reaction is ______.


A solution contains 1 g mol. each of p-toluene diazonium chloride and p-nitrophenyl diazonium chloride. To this 1 g mol. of alkaline solution of phenol is added. Predict the major product. Explain your answer.


Assertion: N, N-Diethylbenzene sulphonamide is insoluble in alkali.

Reason: Sulphonyl group attached to nitrogen atom is strong electron-withdrawing group.


Give reasons for the following observation:

Aniline does not react with methyl chloride in the presence of anhydrous AlCl3 catalyst.


How can the activating effect of the −NH2 group in aniline be controlled?


Assertion (A): Bromination of benzoic acid, gives m-bromobenzoic acid.

Reason (R): Carboxyl group increases the electron density at the meta position.


Aniline does not give Friedel-Crafts reaction. Give a reason.


Given below are two statements:

Statement I: Aniline does not undergo a Friedel-Crafts alkylation reaction.

Statement II: Aniline cannot be prepared through Gabriel synthesis.

In the light of the above statements, choose the correct answer from the options given below:


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