Advertisements
Advertisements
प्रश्न
Write short notes on acetylation.
Advertisements
उत्तर
The process of introducing an acetyl group \[\begin{array}{cc}
\phantom{.....}\ce{O}\\
\phantom{.....}||\\
\ce{(CH3 - C - )}
\end{array}\] into a molecule is called acetylation. The reaction occurs by nucleophilic substitution. There occurs a replacement of the hydrogen atom of −NH2 or > NH by the acetyl group.
Common acetylating agents used are acetyl chloride and acetic anhydride.
\[\begin{array}{cc}
\ce{O}\phantom{................}\ce{O}\phantom{..}\\
||\phantom{.................}||\phantom{..}\\
\ce{CH3CH2NH2 + CH3 - C - Cl -> \underset{N-Ethylacetamide}{CH3 - C - NH - CH2CH3} + HCl}
\end{array}\]
APPEARS IN
संबंधित प्रश्न
How is chlorobenzene prepared from aniline?
What is the action of the following reagents on aniline?
Bromine water
Give reasons for the following:
Aniline does not undergo Friedel- Crafts reaction.
Write the structures of main products when aniline reacts with the following reagents :
Br2 water
Write the structures of main products when aniline reacts with the following reagents :
(CH3CO)2O/pyridine
What is the action of acetic anhydride on diethylamine?
What is the action of the following reagents on aniline?
Hot and conc. sulphuric acid
In the nitration of benzene using a mixture of conc. \[\ce{H2SO4}\] and conc. \[\ce{HNO3}\], the species which initiates the reaction is ______.
What is the role of \[\ce{HNO3}\] in the nitrating mixture used for nitration of benzene?
A solution contains 1 g mol. each of p-toluene diazonium chloride and p-nitrophenyl diazonium chloride. To this 1 g mol. of alkaline solution of phenol is added. Predict the major product. Explain your answer.
Assertion: N, N-Diethylbenzene sulphonamide is insoluble in alkali.
Reason: Sulphonyl group attached to nitrogen atom is strong electron-withdrawing group.
When bromination of aniline is carried out by protecting – NH2. The major product is
Assertion (A): Bromination of benzoic acid, gives m-bromobenzoic acid.
Reason (R): Carboxyl group increases the electron density at the meta position.
Given below are two statements:
Statement I: Aniline does not undergo a Friedel-Crafts alkylation reaction.
Statement II: Aniline cannot be prepared through Gabriel synthesis.
In the light of the above statements, choose the correct answer from the options given below:
Identify the major product C formed in the following reaction sequence:
\[\ce{CH3 - CH2 - CH2 - I ->[NaCN] A ->[OH-][Partial hydrolysis] B ->[NaOH][Br2] \underset{(major)}{C}}\]
