Advertisements
Advertisements
प्रश्न
What is the action of the following reagents on aniline?
Hot and conc. sulphuric acid
Advertisements
उत्तर
Aniline reacts with conc. sulphuric acid to give anilinium hydrogen sulphate which on heating with sulphuric acid at 453-473 K gives p-aminobenzene sulphonic acid (sulphanilic acid ) as a major product.
APPEARS IN
संबंधित प्रश्न
What is the action of acetic anhydride on ethylamine?
What is the action of the following reagents on aniline?
Bromine water
Write the structures of main products when aniline reacts with the following reagents :
Br2 water
Account for the following:
Although the amino group is o, p-directing in aromatic electrophilic substitution reactions, aniline on nitration gives a substantial amount of m-nitroaniline.
Write short notes on acetylation.
What is the action of acetic anhydride on diethylamine?
What is the action of the following reagents on aniline?
Acetic anhydride
How will you convert the following?
Aniline into N−phenylethanamide
In the nitration of benzene using a mixture of conc. \[\ce{H2SO4}\] and conc. \[\ce{HNO3}\], the species which initiates the reaction is ______.
What is the role of \[\ce{HNO3}\] in the nitrating mixture used for nitration of benzene?
A solution contains 1 g mol. each of p-toluene diazonium chloride and p-nitrophenyl diazonium chloride. To this 1 g mol. of alkaline solution of phenol is added. Predict the major product. Explain your answer.
Assertion: N, N-Diethylbenzene sulphonamide is insoluble in alkali.
Reason: Sulphonyl group attached to nitrogen atom is strong electron-withdrawing group.
Give reasons for the following observation:
Aniline is acetylated before nitration reaction.
In the following reaction, the reason for why meta-nitro product also formed is:
How can the activating effect of the −NH2 group in aniline be controlled?
Assertion (A): Bromination of benzoic acid, gives m-bromobenzoic acid.
Reason (R): Carboxyl group increases the electron density at the meta position.
Aniline does not give Friedel-Crafts reaction. Give a reason.
Given below are two statements:
Statement I: Aniline does not undergo a Friedel-Crafts alkylation reaction.
Statement II: Aniline cannot be prepared through Gabriel synthesis.
In the light of the above statements, choose the correct answer from the options given below:
Identify the major product C formed in the following reaction sequence:
\[\ce{CH3 - CH2 - CH2 - I ->[NaCN] A ->[OH-][Partial hydrolysis] B ->[NaOH][Br2] \underset{(major)}{C}}\]
