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प्रश्न
What is the action of acetic anhydride on diethylamine?
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उत्तर
Diethylamine reacts with acetic anhydride to give monoacetyl derivative
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संबंधित प्रश्न
What is the action of acetic anhydride on ethylamine?
What is the action of the following reagents on aniline?
Bromine water
Give reasons for the following:
Aniline does not undergo Friedel- Crafts reaction.
Write the structures of main products when aniline reacts with the following reagents :
Br2 water
Write the structures of main products when aniline reacts with the following reagents :
(CH3CO)2O/pyridine
Write the chemical equations involved when aniline is treated with the following reagents:
Br2 water
Account for the following:
Although the amino group is o, p-directing in aromatic electrophilic substitution reactions, aniline on nitration gives a substantial amount of m-nitroaniline.
Write short notes on acetylation.
What is the action of the following reagents on aniline?
Acetic anhydride
What is the action of the following reagents on aniline?
Hot and conc. sulphuric acid
Illustrate the following reactions giving suitable example in each case
Acetylation of amines
How will you convert the following?
Aniline into N−phenylethanamide
What is the role of \[\ce{HNO3}\] in the nitrating mixture used for nitration of benzene?
Assertion: N, N-Diethylbenzene sulphonamide is insoluble in alkali.
Reason: Sulphonyl group attached to nitrogen atom is strong electron-withdrawing group.
When bromination of aniline is carried out by protecting – NH2. The major product is
Give reasons for the following observation:
Aniline is acetylated before nitration reaction.
Give reasons for the following observation:
Aniline does not react with methyl chloride in the presence of anhydrous AlCl3 catalyst.
Assertion (A): Bromination of benzoic acid, gives m-bromobenzoic acid.
Reason (R): Carboxyl group increases the electron density at the meta position.
Given below are two statements:
Statement I: Aniline does not undergo a Friedel-Crafts alkylation reaction.
Statement II: Aniline cannot be prepared through Gabriel synthesis.
In the light of the above statements, choose the correct answer from the options given below:
Identify the major product C formed in the following reaction sequence:
\[\ce{CH3 - CH2 - CH2 - I ->[NaCN] A ->[OH-][Partial hydrolysis] B ->[NaOH][Br2] \underset{(major)}{C}}\]
