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प्रश्न
Write the IUPAC name of the following compound:
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उत्तर
2,5-Dimethylphenol
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संबंधित प्रश्न
Write the IUPAC name of the following compound:
\[\begin{array}{cc}
\ce{CH3 - CH - CH - CH3}\\
|\phantom{.........}|\phantom{...}\\
\ce{OH}\phantom{....}\ce{OH}\\
\end{array}\]
Give the IUPAC name of the following ether:
Write the structure and IUPAC name of 'methyl-n-propyl ether'.
3-Methylbutane-2-ol on heating with HI gives ______
Write the structures of the products when Butan-2-ol reacts with SOCl2
How do you convert the Ethanal to Propanone
Write a structural formula for methyl vinyl ether.
Write structural formulae for Cyclohex-2-en-1-ol.
Write IUPAC names of the following
Which of the following gives a positive iodoform test?
\[\ce{Phenol ->[Zn, dust] 'X' ->[CH3Cl][Anhy. AlCl3] 'Y' ->[Alkaline][KMnO4] 'Z'}\]
The product ‘Z’ is:
IUPAC name of the compound \[\begin{array}{cc}
\ce{CH3 - CH - OCH3}\\
\phantom{}|\phantom{....}\\
\phantom{}\ce{CH3}\phantom{..}
\end{array}\] is ______.
Which of the following compounds will react with sodium hydroxide solution in water?
Assertion: Addition reaction of water to but-1-ene in acidic medium yields butan-1-ol.
Reason: Addition of water in acidic medium proceeds through the formation of primary carbocation.
Assertion: Like bromination of benzene, bromination of phenol is also carried out in the presence of Lewis acid.
Reason: Lewis acid polarises the bromine molecule.
Assertion: Phenols give o- and p-nitrophenol on nitration with conc. \[\ce{HNO3}\] and \[\ce{H2SO4}\] mixture.
Reason: –OH group in phenol is o–, p– directing.
Identify A and B in the following:
Write IUPAC name of the following compound:
\[\begin{array}{cc}
\phantom{................}\ce{CH3}\\
\phantom{.............}|\\
\ce{CH3 - CH - CH - C - CH3}\\
|\phantom{......}|\phantom{......}|\\
\phantom{...}\ce{CH3}\phantom{..}\ce{OH}\phantom{...}\ce{CH3}
\end{array}\]
The IUPAC name of 
is ______.
Write IUPAC name of the following compound:
\[\begin{array}{cc}
\phantom{...............}\ce{CH3}\\
\phantom{............}|\\
\ce{CH3 - CH - CH - C - CH3}\\
|\phantom{......}|\phantom{......}|\\
\phantom{...}\ce{CH3}\phantom{...}\ce{OH}\phantom{...}\ce{CH3}
\end{array}\]
