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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Which of the following compounds will react with sodium hydroxide solution in water? - Chemistry

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प्रश्न

Which of the following compounds will react with sodium hydroxide solution in water?

पर्याय

  • \[\ce{C6H5OH}\]

  • \[\ce{C6H5CH2OH}\]

  • \[\ce{(CH3)3COH}\]

  • \[\ce{C2H5OH}\]

MCQ
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उत्तर

\[\ce{C6H5OH}\]

Explanation:

Phenol being more acidic reacts with sodium hydroxide solution in water to give sodium phenoxide which is resonance stabilized.

Alcohols are very weak acids.

\[\ce{C6H5OH + NaOH -> C6H5ONa + H2O}\]

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पाठ 11: Alcohols, Phenols and Ethers - Multiple Choice Questions (Type - I) [पृष्ठ १५६]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 12
पाठ 11 Alcohols, Phenols and Ethers
Multiple Choice Questions (Type - I) | Q 11 | पृष्ठ १५६

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\phantom{}|\phantom{....}\\
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\end{array}\] is ______.


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  Column I   Column II
(i) CH3—O—CH3 (a)
(ii) \[\begin{array}{cc}
\ce{CH3}\phantom{..................}\\
\backslash\phantom{.............}\\
\ce{CH-O-CH3}\\
/\phantom{..............}\\
\ce{CH3}\phantom{..................}
\end{array}\]
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\ce{CH3}\phantom{....}\\
|\phantom{.......}\\
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|\phantom{.......}\\
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(iii) \[\begin{array}{cc}
\ce{CH3}\phantom{.}\\
|\phantom{....}\\
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|\phantom{....}\\
\ce{CH3}\phantom{..}
\end{array}\]
(c)
(iv) (d) CH3—OH + CH3—I
    (e) \[\begin{array}{cc}
\ce{CH3}\phantom{.....................}\\
\backslash\phantom{.................}\\
\ce{CH-OH + CH3I}\\
/\phantom{.................}\\
\ce{CH3}\phantom{.....................}
\end{array}\]
    (f) \[\begin{array}{cc}
\ce{CH3}\phantom{.....................}\\
\backslash\phantom{.................}\\
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/\phantom{.................}\\
\ce{CH3}\phantom{.....................}
\end{array}\]
    (g) \[\begin{array}{cc}
\ce{CH3}\phantom{....}\\
|\phantom{.......}\\
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|\phantom{.......}\\
\ce{CH3}\phantom{....}
\end{array}\]

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\phantom{..............}\ce{CH3}\\
\phantom{............}|\\
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|\phantom{.....}|\phantom{......}|\\
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\phantom{................}\ce{CH3}\\
\phantom{.............}|\\
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\phantom{...............}\ce{CH3}\\
\phantom{.............}|\\
\ce{CH3 - CH - CH - C - CH3}\\
|\phantom{......}|\phantom{......}|\\
\phantom{...}\ce{CH3}\phantom{..}\ce{OH}\phantom{...}\ce{CH3}
\end{array}\]


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