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प्रश्न
Give IUPAC name of the compound given below.
\[\begin{array}{cc}
\phantom{}\ce{CH3 - CH - CH2 - CH2 - CH - CH3}\phantom{.}\\
\phantom{.........}|\phantom{...................}|\phantom{...........}\\
\phantom{..}\ce{Cl}\phantom{.................}\ce{OH}\phantom{..}
\end{array}\]
पर्याय
2-Chloro-5-hydroxyhexane
2-Hydroxy-5-chlorohexane
5-Chlorohexan-2-ol
2-Chlorohexan-5-ol
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उत्तर
5-Chlorohexan-2-ol
Explanation:
\[\begin{array}{cc}
\ce{\overset{6}{C}H3-\overset{5}{C}H-\overset{4}{C}H2-\overset{3}{C}H2-\overset{2}{C}H-\overset{1}{C}H3}\\
\phantom{}|\phantom{.................}|\phantom{..}\\
\phantom{....}\ce{\underset{5-Chlorohexan-2-ol}{Cl\phantom{...............}OH}}\phantom{....}
\end{array}\]
APPEARS IN
संबंधित प्रश्न
Name the following compound according to IUPAC system.
\[\begin{array}{cc}
\phantom{............}\ce{CH2OH}\\
\phantom{......}|\\
\ce{CH3 - CH2 - CH - CH - CH - CH3}\\
\phantom{......}|\phantom{............}|\phantom{.}\\
\phantom{........}\ce{CH2Cl}\phantom{......}\ce{CH3}\phantom{}
\end{array}\]
Write IUPAC name of the following compound:
\[\begin{array}{cc}
\ce{CH3 - O - CH2 - CH - CH3}\\
\phantom{..........}|\\
\phantom{............}\ce{CH3}
\end{array}\]
Write IUPAC name of the following compound:
C6H5 – O – C7H15(n−)
Write IUPAC name of the following compound (CH3)2 N − CH2CH3
Write the IUPAC name of the following compound:
Glycerol is ____________.
3-methylphenol is called ____________.
Ethyl alcohol is industrially prepared from ethylene by:
1-Propanol and 2-propanol can be best distinguished by:
\[\ce{Phenol ->[Zn, dust] 'X' ->[CH3Cl][Anhy. AlCl3] 'Y' ->[Alkaline][KMnO4] 'Z'}\]
The product ‘Z’ is:
The correct acidic strength order of the following is:
(I)
(II)
(III)
Which of the following reagents can be used to oxidise primary alcohols to aldehydes?
(i) \[\ce{CrO3}\] in anhydrous medium.
(ii) \[\ce{KMnO4}\] in acidic medium.
(iii) Pyridinium chlorochromate.
(iv) Heat in the presence of Cu at 573 K.
Match the structures of the compounds given in Column I with the name of the compounds given in Column II.
| Column I | Column II | |
| (i) |  |
(a) Hydroquinone |
| (ii) |  |
(b) Phenetole |
| (iii) |  |
(c) Catechol |
| (iv) |  |
(d) o-Cresol |
| (v) |  |
(e) guinone |
| (vi) |  |
(f) Resorcinol |
| (g) Anisole |
Match the starting materials given in Column I with the products formed by these (Column II) in the reaction with HI.
| Column I | Column II | ||
| (i) | CH3—O—CH3 | (a) |  |
| (ii) | \[\begin{array}{cc} \ce{CH3}\phantom{..................}\\ \backslash\phantom{.............}\\ \ce{CH-O-CH3}\\ /\phantom{..............}\\ \ce{CH3}\phantom{..................} \end{array}\] |
(b) | \[\begin{array}{cc} \ce{CH3}\phantom{....}\\ |\phantom{.......}\\ \ce{CH3-C-I + CH3OH}\\ |\phantom{.......}\\ \ce{CH3}\phantom{....} \end{array}\] |
| (iii) | \[\begin{array}{cc} \ce{CH3}\phantom{.}\\ |\phantom{....}\\ \ce{H3C-C-O-CH3}\\ |\phantom{....}\\ \ce{CH3}\phantom{..} \end{array}\] |
(c) |  |
| (iv) |  |
(d) | CH3—OH + CH3—I |
| (e) | \[\begin{array}{cc} \ce{CH3}\phantom{.....................}\\ \backslash\phantom{.................}\\ \ce{CH-OH + CH3I}\\ /\phantom{.................}\\ \ce{CH3}\phantom{.....................} \end{array}\] |
||
| (f) | \[\begin{array}{cc} \ce{CH3}\phantom{.....................}\\ \backslash\phantom{.................}\\ \ce{CH-I + CH3OH}\\ /\phantom{.................}\\ \ce{CH3}\phantom{.....................} \end{array}\] |
||
| (g) | \[\begin{array}{cc} \ce{CH3}\phantom{....}\\ |\phantom{.......}\\ \ce{CH3-C-OH + CH3I}\\ |\phantom{.......}\\ \ce{CH3}\phantom{....} \end{array}\] |
Assertion: Phenol forms 2, 4, 6 – tribromophenol on treatment with \[\ce{Br2}\] in carbon disulphide at 273 K.
Reason: Bromine polarises in carbon disulphide.
Assertion: Phenols give o- and p-nitrophenol on nitration with conc. \[\ce{HNO3}\] and \[\ce{H2SO4}\] mixture.
Reason: –OH group in phenol is o–, p– directing.
How can phenol be converted to aspirin?
Write structural formulae for:
Salicylic acid
Write IUPAC names of the following compounds:
\[\begin{array}{cc}
\phantom{...............}\ce{CH3}\\
\phantom{.............}|\\
\ce{CH3 - CH - CH - C - CH3}\\
|\phantom{......}|\phantom{......}|\\
\phantom{...}\ce{CH3\phantom{...}OH\phantom{...}CH3}\\
\end{array}\]
