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प्रश्न
A regular hexagon of side 10 cm has a charge 5 µC at each of its vertices. Calculate the potential at the centre of the hexagon.
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उत्तर
The given figure shows six equal amounts of charges q at the vertices of a regular hexagon.

Where,
Charge, q = 5 µC = 5 × 10−6 C
Side of the hexagon, l = AB = BC = CD = DE = EF = FA = 10 cm
Distance of each vertex from centre O,
d = 10 cm
Electric potential at point O,
`V = (6 xx q)/(4pi ε_0 d)`
Where,
`ε_0` = Permittivity of free space
`1/(4pi ε_0) = 9 xx 10^9` N C−2 m−2
∴ `V = (6 xx 9 xx 10^9 xx 5 xx 10^-6)/0.1`
= 270 × 103
= 2.7 × 106 V
Therefore, the potential at the centre of the hexagon is 2.7 × 106 V.
संबंधित प्रश्न
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(b) a field that uniformly increases in magnitude but remains in a constant (say, z) direction,
(c) a single positive charge at the origin, and
(d) a uniform grid consisting of long equally spaced parallel charged wires in a plane.
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Draw equipotential surfaces:
(1) in the case of a single point charge and
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(3) Can electric field exist tangential to an equipotential surface? Give reason
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The diagrams below show regions of equipotentials.
(i)![]() |
(ii)![]() |
(iii)![]() |
(iv)![]() |
A positive charge is moved from A to B in each diagram.
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- Work done in moving a charge from one point to other on an equipotential surface is zero.
Find the equation of the equipotentials for an infinite cylinder of radius r0, carrying charge of linear density λ.
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