मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

A man fixes outside his house one evening a two metre high insulating slab carrying on its top a large aluminium sheet of area 1 m2.

Advertisements
Advertisements

प्रश्न

A man fixes outside his house one evening a two metre high insulating slab carrying on its top a large aluminium sheet of area 1 m2. Will he get an electric shock if he touches the metal sheet next morning?

टीपा लिहा
Advertisements

उत्तर

Yes, the man will get an electric shock if he touches the metal slab next morning. The steady discharging current in the atmosphere charges up the aluminium sheet. As a result, its voltage rises gradually. The rise in the voltage depends on the capacitance of the capacitor formed by the aluminium slab and the ground.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2: Electrostatic Potential and Capacitance - Exercise [पृष्ठ ९१]

APPEARS IN

एनसीईआरटी Physics Part I and II [English] Class 12
पाठ 2 Electrostatic Potential and Capacitance
Exercise | Q 2.36 (b) | पृष्ठ ९१

संबंधित प्रश्‍न

Two charges 2 μC and −2 µC are placed at points A and B 6 cm apart.

  1. Identify an equipotential surface of the system.
  2. What is the direction of the electric field at every point on this surface?

Describe schematically the equipotential surfaces corresponding to

(a) a constant electric field in the z-direction,

(b) a field that uniformly increases in magnitude but remains in a constant (say, z) direction,

(c) a single positive charge at the origin, and

(d) a uniform grid consisting of long equally spaced parallel charged wires in a plane.


The discharging current in the atmosphere due to the small conductivity of air is known to be 1800 A on an average over the globe. Why then does the atmosphere not discharge itself completely in due course and become electrically neutral? In other words, what keeps the atmosphere charged?


Draw equipotential surfaces:

(1) in the case of a single point charge and

(2) in a constant electric field in Z-direction. Why are the equipotential surfaces about a single charge not equidistant?

(3) Can electric field exist tangential to an equipotential surface? Give reason


Two identical point charges, q each, are kept 2m apart in the air. A third point charge Q of unknown magnitude and sign is placed on the line joining the charges such that the system remains in equilibrium. Find the position and nature of Q.


Draw the equipotential surfaces due to an electric dipole.


Find the amount of work done in rotating an electric dipole of dipole moment 3.2 x 10- 8Cm from its position of stable equilibrium to the position of unstable equilibrium in a uniform electric field if intensity 104 N/C.  


S1 and S2 are the two imaginary surfaces enclosing the charges +q and -q as shown. The electric flux through S1 and S2 are respectively ______.


Assertion: Electric field is discontinuous across the surface of a spherical charged shell.
Reason: Electric potential is continuous across the surface of a spherical charged shell.


Equipotentials at a great distance from a collection of charges whose total sum is not zero are approximately.


An equipotential surface is that surface ______.

Can two equipotential surfaces intersect each other? 


Consider a uniform electric field in the ẑ direction. The potential is a constant ______.

  1. in all space.
  2. for any x for a given z.
  3. for any y for a given z.
  4. on the x-y plane for a given z.

The work done to move a charge along an equipotential from A to B ______.

  1. cannot be defined as `- int_A^B E.dl`
  2. must be defined as `- int_A^B E.dl`
  3. is zero.
  4. can have a non-zero value.

Prove that a closed equipotential surface with no charge within itself must enclose an equipotential volume.


Find the equation of the equipotentials for an infinite cylinder of radius r0, carrying charge of linear density λ.


Equipotential surfaces are shown in figure. Then the electric field strength will be ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×