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प्रश्न
Two charges 2 μC and −2 µC are placed at points A and B 6 cm apart.
- Identify an equipotential surface of the system.
- What is the direction of the electric field at every point on this surface?
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उत्तर
- The situation is represented in the given figure.
An equipotential surface is a plane on which total potential is zero everywhere. This plane is normal to line AB. The plane is located at the mid-point of line AB because the magnitude of charges is the same. - The direction of the electric field at every point on this surface is normal to the plane in the direction of AB.
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संबंधित प्रश्न
A regular hexagon of side 10 cm has a charge 5 µC at each of its vertices. Calculate the potential at the centre of the hexagon.
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(a) a constant electric field in the z-direction,
(b) a field that uniformly increases in magnitude but remains in a constant (say, z) direction,
(c) a single positive charge at the origin, and
(d) a uniform grid consisting of long equally spaced parallel charged wires in a plane.
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What is the geometrical shape of equipotential surfaces due to a single isolated charge?
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Depict the equipotential surface due to
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Reason: Electric potential is continuous across the surface of a spherical charged shell.
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- No two equipotential surfaces can intersect each other.
- Electric field lines are in the direction of tangent to an equipotential surface.
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(i) |
(ii) |
(iii) |
(iv) |
A positive charge is moved from A to B in each diagram.
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Find the equation of the equipotentials for an infinite cylinder of radius r0, carrying charge of linear density λ.
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