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A regular hexagon of side 10 cm has a charge 5 µC at each of its vertices. Calculate the potential at the centre of the hexagon. - Physics

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प्रश्न

A regular hexagon of side 10 cm has a charge 5 µC at each of its vertices. Calculate the potential at the centre of the hexagon.

संख्यात्मक
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उत्तर

The given figure shows six equal amounts of charges, q, at the vertices of a regular hexagon.

Where,

Charge, q = 5 µC = 5 × 10−6 C

Side of the hexagon, l = AB = BC = CD = DE = EF = FA = 10 cm

Distance of each vertex from centre O, d = 10 cm

Electric potential at point O,

`V = (6 xx q)/(4pi in_0 d)`

Where,

`in_0` = Permittivity of free space

`1/(4pi in_0) = 9 xx 10^9 NC^-2 m^-2`

∴ `V = (6 xx 9 xx 10^9 xx 5 xx 10^-6)/0.1`

= 2.7 × 106 V

Therefore, the potential at the centre of the hexagon is 2.7 × 106 V.

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अध्याय 2: Electrostatic Potential and Capacitance - EXERCISES [पृष्ठ ७९]

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एनसीईआरटी Physics [English] Class 12
अध्याय 2 Electrostatic Potential and Capacitance
EXERCISES | Q 2.2 | पृष्ठ ७९

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