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प्रश्न
Equipotentials at a great distance from a collection of charges whose total sum is not zero are approximately.
विकल्प
spheres
planes
paraboloids
ellipsoids
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उत्तर
spheres
Explanation:
The collection of charges, whose total sum is not zero, with regard to great distance can be considered as a single-point charge. The equipotential surfaces due to a point charge are spherical.
Important point:
- The electric potential due to point charge q is given by V = q/4πε0r
- It means electric potential due to point charge is same for all equidistant points. The locus of these equidistant points, which are at the same potential, form spherical surface.
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संबंधित प्रश्न
Define an equipotential surface.
Draw equipotential surfaces:
(1) in the case of a single point charge and
(2) in a constant electric field in Z-direction. Why are the equipotential surfaces about a single charge not equidistant?
(3) Can electric field exist tangential to an equipotential surface? Give reason
Draw the equipotential surfaces due to an electric dipole. Locate the points where the potential due to the dipole is zero.
Define equipotential surface.
Two identical point charges, q each, are kept 2m apart in the air. A third point charge Q of unknown magnitude and sign is placed on the line joining the charges such that the system remains in equilibrium. Find the position and nature of Q.
Depict the equipotential surface due to
(i) an electric dipole,
(ii) two identical positive charges separated by a distance.
Find the amount of work done in rotating an electric dipole of dipole moment 3.2 x 10- 8Cm from its position of stable equilibrium to the position of unstable equilibrium in a uniform electric field if intensity 104 N/C.
Statement - 1: For practical purpose, the earth is used as a reference at zero potential in electrical circuits.
Statement - 2: The electrical potential of a sphere of radius R with charge Q uniformly distributed on the surface is given by `Q/(4piepsilon_0R)`.
Assertion: Electric field is discontinuous across the surface of a spherical charged shell.
Reason: Electric potential is continuous across the surface of a spherical charged shell.
- The potential at all the points on an equipotential surface is same.
- Equipotential surfaces never intersect each other.
- Work done in moving a charge from one point to other on an equipotential surface is zero.
Which of the following is NOT the property of equipotential surface?
Can two equipotential surfaces intersect each other?
The direction in which electric potential decreases is:
The surface of any conductor in electrostatic equilibrium is an equipotential surface because:
What is the shape of the equipotential surfaces for a single point charge (+q)?
The relation between the electric field \[\vec{E}\] and the potential gradient is expressed as:
A particle floats between two parallel plates separated by 0.1 m with a potential difference of 4000 V. The particle carries a charge of \[1.6 \times 10^{-19}\] C. Taking \[g = 9.8\ \text{m/s}^2\], the mass of the particle is approximately:
A point charge of \[1\ \mu\text{C}\] produces a potential \[V = \frac{kq}{r}\]. At what distance from the charge does the potential equal 90 V? (Take \[k = 9 \times 10^9\ \text{N m}^2/\text{C}^2\])
