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प्रश्न
Which of the following is NOT the property of equipotential surface?
विकल्प
They do not cross each other.
The rate of change of potential with distance on them is zero.
For a uniform electric field, they are concentric spheres.
They can be imaginary spheres.
The work done in carrying a charge from one point to another on an equipotential surface is zero.
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उत्तर
For a uniform electric field, they are concentric spheres.
Explanation:
As all other statements are correct. In a uniform electric field, equipotential surfaces are never concentric spheres but are planes ⊥ to Electric field lines.
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संबंधित प्रश्न
What is the geometrical shape of equipotential surfaces due to a single isolated charge?
Why is there no work done in moving a charge from one point to another on an equipotential surface?
Assertion: Electric field is discontinuous across the surface of a spherical charged shell.
Reason: Electric potential is continuous across the surface of a spherical charged shell.
Consider the following statements and select the correct statement(s).
- Electric field lines are always perpendicular to equipotential surface.
- No two equipotential surfaces can intersect each other.
- Electric field lines are in the direction of tangent to an equipotential surface.
Can two equipotential surfaces intersect each other?
Equipotential surfaces are denser (closer together) in regions where:
What is the shape of the equipotential surfaces for a single point charge (+q)?
For an infinite line charge (infinite cylinder configuration), the equipotential surfaces are:
In the derivation proving \[\vec{E}\] is perpendicular to an equipotential surface, a charge \[q_0\] undergoes a small displacement \[d\vec{l}\] along the surface, with \[\vec{E}\] making an angle \[\theta\] with the displacement. Equating the work expressions leads to which conclusion?
A particle floats between two parallel plates separated by 0.1 m with a potential difference of 4000 V. The particle carries a charge of \[1.6 \times 10^{-19}\] C. Taking \[g = 9.8\ \text{m/s}^2\], the mass of the particle is approximately:
