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R.S. Aggarwal solutions for मैथमैटिक्स [अंग्रेजी] कक्षा १० chapter 12 - Trigonometric Ratios of Some Complemantary Angles [Latest edition]

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R.S. Aggarwal solutions for मैथमैटिक्स [अंग्रेजी] कक्षा १० chapter 12 - Trigonometric Ratios of Some Complemantary Angles - Shaalaa.com
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Solutions for Chapter 12: Trigonometric Ratios of Some Complemantary Angles

Below listed, you can find solutions for Chapter 12 of CBSE, Karnataka Board R.S. Aggarwal for मैथमैटिक्स [अंग्रेजी] कक्षा १०.


EXERCISE 12MULTIPLE-CHOICE QUESTIONS (MCQ)
EXERCISE 12 [Pages 590 - 591]

R.S. Aggarwal solutions for मैथमैटिक्स [अंग्रेजी] कक्षा १० 12 Trigonometric Ratios of Some Complemantary Angles EXERCISE 12 [Pages 590 - 591]

1. (i)Page 590

Without using trigonometric tables, evaluate:

`(sin 26^circ)/(cos 64^circ)`

1. (ii)Page 590

Without using trigonometric tables, evaluate:

`sec 11^circ/("cosec"  79^circ)`

1. (iii)Page 590

Without using trigonometric tables, evaluate:

`(tan 65^circ)/(cot 25^circ)`

1. (iv)Page 590

Without using trigonometric tables, evaluate:

`(cos 37^circ)/(sin 53^circ)`

1. (v)Page 590

Without using trigonometric tables, evaluate:

`("cosec"  42^circ)/sec 48^circ`

1. (vi)Page 590

Without using trigonometric tables, evaluate:

`(tan 35^circ)/(cot 55^circ) + (cot 78^circ)/(tan 12^circ) = 2`

2. (i)Page 590

Without using trigonometric tables, prove that:

cos 81° – sin 9° = 0

2. (ii)Page 590

Without using trigonometric tables, prove that:

tan 71° – cot 19° = 0

2. (iii)Page 590

Without using trigonometric tables, prove that:

cosec 60° – sec 30° = 0

2. (iv)Page 590

Without using trigonometric tables, prove that:

cot 34° – tan 56° = 0

2. (v)Page 590

Without using trigonometric tables, prove that:

sin248° + sin242° = 1

2. (vi)Page 590

Without using trigonometric tables, prove that:

cos272° + cos218° = 1

3. (i)Page 590

Without using trigonometric tables, prove that:

sin212° + sin278° = 1

3. (ii)Page 590

Without using trigonometric tables, prove that:

sec229° – cot261° = 1

3. (iii)Page 590

Without using trigonometric tables, prove that:

tan256° – cot234° = 0

3. (iv)Page 590

Without using trigonometric tables, prove that:

cos257° – sin233° = 0

3. (v)Page 590

Without using trigonometric tables, prove that:

sec250° – cot240° = 1

3. (vi)Page 590

Without using trigonometric tables, prove that:

cosec272° – tan218° = 1

4. (i)Page 590

Without using trigonometric tables, prove that:

sin 32° cos 58° + cos 32° sin 58° = 1

4. (ii)Page 590

Without using trigonometric tables, prove that:

cos 54° cos 36° – sin 54° sin 36° = 0

4. (iii)Page 590

Without using trigonometric tables, prove that:

sec 70° sin 20° + cos 20° cosec 70° = 2

4. (iv)Page 590

Without using trigonometric tables, prove that:

tan 15° tan 60° tan 75° = `sqrt(3)`

4. (v)Page 590

Without using trigonometric tables, prove that:

tan 48° tan 23° tan 42° tan 67° tan 45° = 1

4. (vi)Page 590

Without using trigonometric tables, prove that:

(sin 72° + cos 18°)(sin 72° – cos 18°) = 0

4. (vii)Page 590

Without using trigonometric tables, prove that:

cosec 39° cos 51° + tan 21° cot 69° – sec221° = 0

5. (i)Page 590

Express the following in terms of trigonometric ratios of angles between 0° and 45°.

sin 72° + cosec 72°

5. (ii)Page 590

Express the following in terms of trigonometric ratios of angles between 0° and 45°.

cosec 66° + tan 66°

5. (iii)Page 590

Express the following in terms of trigonometric ratios of angles between 0° and 45°.

tan 68° + sec 68°

5. (iv)Page 590

Express the following in terms of trigonometric ratios of angles between 0° and 45°.

cot 59° + cosec 59°

5. (v)Page 590

Express the following in terms of trigonometric ratios of angles between 0° and 45°.

cos 51° + cot 49° – sec 47°

5. (vi)Page 590

Express the following in terms of trigonometric ratios of angles between 0° and 45°.

sin 67° + cos 75°

6.Page 591

If sin 3A = cos (A – 10°), where 3A is an acute angle then find ∠A.

7.Page 591

If tan A = cot (A + 10°), where (A + 10°) is acute then find ∠A.

8.Page 591

If cos 2A = sin (A – 15°), where 2A is acute then find ∠A.

9.Page 591

If sec 4A = cosec (A – 15°), where 4A is acute then find ∠A.

10.Page 591

If tan 2θ = cot (θ + 6º), where 2θ and (θ + 6º) are acute angles, find the value of θ.

11.Page 591

If sin (θ + 36°) = cos θ, where (θ + 36°) is acute, find θ.

12.Page 591

Without using trigonometric tables, find the value of the expression:

3 cot 31° tan 15° cot 27° tan 75° cot 63° cot 59°

13.Page 591

Without using trigonometric tables, find the value of the expression:

`2((cos 58^circ)/(sin 32^circ)) - sqrt(3)((cos 38^circ "cosec"  52^circ)/(tan 15^circ tan 60^circ tan 75^circ))`

14.Page 591

Without using trigonometric tables, find the value of the expression:

`{(cos 70^circ)/(sin 20^circ) + (cos 55^circ "cosec"  35^circ)/(tan 5^circ tan 25^circ tan 45^circ tan 65^circ tan 85^circ)}`

15.Page 591

Without using trigonometric tables, find the value of the expression:

`{(sin^2 22^circ + sin^2 68^circ)/(cos^2 22^circ + cos^2 68^circ) + sin^2 63^circ + cos 63^circ sin 27^circ}`

16.Page 591

Without using trigonometric tables, find the value of the expression:

`{(cos 65^circ)/(sin 25^circ) + ("cosec"  34^circ)/(sec 56^circ) - (2 cos 43^circ "cosec"  47^circ)/(tan 10^circ tan 40^circ tan 50^circ tan 80^circ)}`

17.Page 591

Without using trigonometric tables, find the value of the expression:

`cot θ tan (90^circ - θ) - sec (90^circ - θ)"cosec"  θ + sin^2 65^circ + sin^2 25^circ + sqrt(3) tan 5^circ tan 45^circ tan 85^circ`

18.Page 591

Without using trigonometric tables, find the value of the expression:

`(sec (90^circ - θ)"cosec"  θ - tan (90^circ - θ)cot θ + cos^2 25^circ + cos^2 65^circ)/(3 tan 27^circ tan 63^circ)`

19.Page 591

Without using trigonometric tables, find the value of the expression:

`(cos(90^circ - θ) sec(90^circ - θ) tan θ)/("cosec"(90^circ - θ)sin(90^circ - θ)cot(90^circ - θ)) + (tan(90^circ - θ))/(cot θ)`

20.Page 591

Without using trigonometric tables, find the value of the expression:

sin (50° + θ) – cos (40° – θ) + tan 1° tan 10° tan 20° tan 70° tan 80° tan 89°

21.Page 591

Show that `(cos^2(45^circ + θ) + cos^2(45^circ - θ))/(tan(60^circ + θ) tan(30^circ - θ)) = 1`.

MULTIPLE-CHOICE QUESTIONS (MCQ) [Pages 593 - 594]

R.S. Aggarwal solutions for मैथमैटिक्स [अंग्रेजी] कक्षा १० 12 Trigonometric Ratios of Some Complemantary Angles MULTIPLE-CHOICE QUESTIONS (MCQ) [Pages 593 - 594]

Choose the correct answer in each of the following questions:

1.Page 593

`(sec 32^circ)/("cosec"  58^circ)` = ?

  • `2/3`

  • `16/29`

  • `16/3`

  • 1

2.Page 593

`(cos 12^circ)/(sin 78^circ) + (tan 23^circ)/(cot 67^circ)` = ?

  • 0

  • 1

  • 2

  • `3/2`

3.Page 593

tan 10° tan 15° tan 75° tan 80° = ?

  • `sqrt(3)`

  • 1

  • `1/sqrt(3)`

  • –1

4.Page 593

tan 5° tan 25° tan 30° tan 65° tan 85° = ?

  • 1

  • `sqrt(3)`

  • `1/sqrt(3)`

  • `1/2`

5.Page 593

cos 1° cos 2° cos 3°... cos 180° = ?

  • 0

  • 1

  • –1

  • `1/2`

6.Page 593

sin 43° cos 47° + cos 43° sin 47° = ?

  • 0

  • 1

  • sin 4°

  • cos 4°

7.Page 593

sec 70° sin 20° + cos 20° cosec 70° = ?

  • 0

  • 1

  • 2

  • –2

8.Page 593

cosec2 57° – tan2 33° = ?

  • 1

  • 0

  • –1

  • 2

9.Page 593

sec2 10° – cot2 80° = ?

  • 0

  • 1

  • `3/4`

  • `1/2`

10.Page 593

`(2 sin^2 63^circ + 1 + 2 sin^2 27^circ)/(3 cos^2 17^circ - 2 + 3 cos^2 73^circ)` = ?

  • `2/3`

  • `3/2`

  • 2

  • 3

11.Page 594

sin 38° – cos 52° = ?

  • 0

  • 1

  • `sqrt(3)/2`

  • `2/sqrt(3)`

12.Page 594

`((sin^2 23^circ + sin^2 67^circ))/((cos^2 13^circ + cos^2 77^circ)) + sin^2 59^circ + cos 59^circ sin 21^circ` = ?

  • 3

  • 2

  • 1

  • 0

13.Page 594

`((2 tan^2 30^circ sec^2 52^circ sin^2 38^circ)/("cosec"^2 70^circ - tan^2 20^circ))` = ?

  • 2

  • 1

  • `2/3`

  • `3/2`

14.Page 594

`((cos 38^circ "cosec"  52^circ)/(tan 18^circ tan 35^circ tan 60^circ tan 72^circ tan 55^circ))` = ?

  • `1/3`

  • `1/sqrt(3)`

  • `sqrt(3)`

  • `2/sqrt(3)`

15.Page 594

sin (60° + θ) – cos (30° – θ) = ?

  • 2 sin θ

  • 2 cos θ

  • 0

  • 1

16.Page 594

If A and B are acute angles such that sin A = cos B then (A + B) = ?

  • 30°

  • 45°

  • 60°

  • 90°

17.Page 594

If cos (α + β) = 0 then sin (α – β) = ?

  • sin 2α

  • cos 2β

  • sin α

  • cos β

18.Page 594

sin (45° + θ) – cos (45° – θ) = ?

  • 0

  • 1

  • 2

  • –2

19.Page 594

If sec 4A = cosec (A – 10°) and 4A is acute then A = ?

  • 20°

  • 25°

  • 30°

  • 40°

20.Page 594

If sin 3A = cos (A – 10°) and 3A is acute then A =?

  • 15°

  • 20°

  • 25°

  • 30°

Fill in the blanks.

21. (i)Page 594

cot 34° – tan 56° = .....

21. (ii)Page 594

cosec 31° – sec 59° = ......

21. (iii)Page 594

cos267° + cos223° = ......

21. (iv)Page 594

cosec254° – tan236° = ......

21. (v)Page 594

sec240° – cot250° = ......

Solutions for 12: Trigonometric Ratios of Some Complemantary Angles

EXERCISE 12MULTIPLE-CHOICE QUESTIONS (MCQ)
R.S. Aggarwal solutions for मैथमैटिक्स [अंग्रेजी] कक्षा १० chapter 12 - Trigonometric Ratios of Some Complemantary Angles - Shaalaa.com

R.S. Aggarwal solutions for मैथमैटिक्स [अंग्रेजी] कक्षा १० chapter 12 - Trigonometric Ratios of Some Complemantary Angles

Shaalaa.com has the CBSE, Karnataka Board Mathematics मैथमैटिक्स [अंग्रेजी] कक्षा १० CBSE, Karnataka Board solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. R.S. Aggarwal solutions for Mathematics मैथमैटिक्स [अंग्रेजी] कक्षा १० CBSE, Karnataka Board 12 (Trigonometric Ratios of Some Complemantary Angles) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

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Concepts covered in मैथमैटिक्स [अंग्रेजी] कक्षा १० chapter 12 Trigonometric Ratios of Some Complemantary Angles are .

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