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1: Real Numbers
Algebra
2: Polynomials
3: Linear Equations in Two Variables
4: Quadratic Equations
5: Arithmetic Progression
Coordinate Geometry
6: Coordinate Geometry
Geometry
7: Triangles
8: Circles
9: Constructions
Trigonometry
10: Trignometric Ratios
11: T-Ratios of Some Particular Angles
▶ 12: Trigonometric Ratios of Some Complemantary Angles
13: Trigonometric identities
14: Heights and Distances
Mensuration
15: Perimeter And Area of Plane Figures
16: Area of Circle, Sector and Segment
17: Volumes and Surface Areas of Solids
Statistics and Probability
18: Mean, Median, Mode of Grouped Data, Cumulative Frequency Graph and Ogive
19: Probability
Chapter 20: Additional Questions
![R.S. Aggarwal solutions for मैथमैटिक्स [अंग्रेजी] कक्षा १० chapter 12 - Trigonometric Ratios of Some Complemantary Angles R.S. Aggarwal solutions for मैथमैटिक्स [अंग्रेजी] कक्षा १० chapter 12 - Trigonometric Ratios of Some Complemantary Angles - Shaalaa.com](/images/mathematics-english-class-10_6:8f062ea57bdf49abb4f6d22550b39d56.jpg)
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Solutions for Chapter 12: Trigonometric Ratios of Some Complemantary Angles
Below listed, you can find solutions for Chapter 12 of CBSE, Karnataka Board R.S. Aggarwal for मैथमैटिक्स [अंग्रेजी] कक्षा १०.
R.S. Aggarwal solutions for मैथमैटिक्स [अंग्रेजी] कक्षा १० 12 Trigonometric Ratios of Some Complemantary Angles EXERCISE 12 [Pages 590 - 591]
Without using trigonometric tables, evaluate:
`(sin 26^circ)/(cos 64^circ)`
Without using trigonometric tables, evaluate:
`sec 11^circ/("cosec" 79^circ)`
Without using trigonometric tables, evaluate:
`(tan 65^circ)/(cot 25^circ)`
Without using trigonometric tables, evaluate:
`(cos 37^circ)/(sin 53^circ)`
Without using trigonometric tables, evaluate:
`("cosec" 42^circ)/sec 48^circ`
Without using trigonometric tables, evaluate:
`(tan 35^circ)/(cot 55^circ) + (cot 78^circ)/(tan 12^circ) = 2`
Without using trigonometric tables, prove that:
cos 81° – sin 9° = 0
Without using trigonometric tables, prove that:
tan 71° – cot 19° = 0
Without using trigonometric tables, prove that:
cosec 60° – sec 30° = 0
Without using trigonometric tables, prove that:
cot 34° – tan 56° = 0
Without using trigonometric tables, prove that:
sin248° + sin242° = 1
Without using trigonometric tables, prove that:
cos272° + cos218° = 1
Without using trigonometric tables, prove that:
sin212° + sin278° = 1
Without using trigonometric tables, prove that:
sec229° – cot261° = 1
Without using trigonometric tables, prove that:
tan256° – cot234° = 0
Without using trigonometric tables, prove that:
cos257° – sin233° = 0
Without using trigonometric tables, prove that:
sec250° – cot240° = 1
Without using trigonometric tables, prove that:
cosec272° – tan218° = 1
Without using trigonometric tables, prove that:
sin 32° cos 58° + cos 32° sin 58° = 1
Without using trigonometric tables, prove that:
cos 54° cos 36° – sin 54° sin 36° = 0
Without using trigonometric tables, prove that:
sec 70° sin 20° + cos 20° cosec 70° = 2
Without using trigonometric tables, prove that:
tan 15° tan 60° tan 75° = `sqrt(3)`
Without using trigonometric tables, prove that:
tan 48° tan 23° tan 42° tan 67° tan 45° = 1
Without using trigonometric tables, prove that:
(sin 72° + cos 18°)(sin 72° – cos 18°) = 0
Without using trigonometric tables, prove that:
cosec 39° cos 51° + tan 21° cot 69° – sec221° = 0
Express the following in terms of trigonometric ratios of angles between 0° and 45°.
sin 72° + cosec 72°
Express the following in terms of trigonometric ratios of angles between 0° and 45°.
cosec 66° + tan 66°
Express the following in terms of trigonometric ratios of angles between 0° and 45°.
tan 68° + sec 68°
Express the following in terms of trigonometric ratios of angles between 0° and 45°.
cot 59° + cosec 59°
Express the following in terms of trigonometric ratios of angles between 0° and 45°.
cos 51° + cot 49° – sec 47°
Express the following in terms of trigonometric ratios of angles between 0° and 45°.
sin 67° + cos 75°
If sin 3A = cos (A – 10°), where 3A is an acute angle then find ∠A.
If tan A = cot (A + 10°), where (A + 10°) is acute then find ∠A.
If cos 2A = sin (A – 15°), where 2A is acute then find ∠A.
If sec 4A = cosec (A – 15°), where 4A is acute then find ∠A.
If tan 2θ = cot (θ + 6º), where 2θ and (θ + 6º) are acute angles, find the value of θ.
If sin (θ + 36°) = cos θ, where (θ + 36°) is acute, find θ.
Without using trigonometric tables, find the value of the expression:
3 cot 31° tan 15° cot 27° tan 75° cot 63° cot 59°
Without using trigonometric tables, find the value of the expression:
`2((cos 58^circ)/(sin 32^circ)) - sqrt(3)((cos 38^circ "cosec" 52^circ)/(tan 15^circ tan 60^circ tan 75^circ))`
Without using trigonometric tables, find the value of the expression:
`{(cos 70^circ)/(sin 20^circ) + (cos 55^circ "cosec" 35^circ)/(tan 5^circ tan 25^circ tan 45^circ tan 65^circ tan 85^circ)}`
Without using trigonometric tables, find the value of the expression:
`{(sin^2 22^circ + sin^2 68^circ)/(cos^2 22^circ + cos^2 68^circ) + sin^2 63^circ + cos 63^circ sin 27^circ}`
Without using trigonometric tables, find the value of the expression:
`{(cos 65^circ)/(sin 25^circ) + ("cosec" 34^circ)/(sec 56^circ) - (2 cos 43^circ "cosec" 47^circ)/(tan 10^circ tan 40^circ tan 50^circ tan 80^circ)}`
Without using trigonometric tables, find the value of the expression:
`cot θ tan (90^circ - θ) - sec (90^circ - θ)"cosec" θ + sin^2 65^circ + sin^2 25^circ + sqrt(3) tan 5^circ tan 45^circ tan 85^circ`
Without using trigonometric tables, find the value of the expression:
`(sec (90^circ - θ)"cosec" θ - tan (90^circ - θ)cot θ + cos^2 25^circ + cos^2 65^circ)/(3 tan 27^circ tan 63^circ)`
Without using trigonometric tables, find the value of the expression:
`(cos(90^circ - θ) sec(90^circ - θ) tan θ)/("cosec"(90^circ - θ)sin(90^circ - θ)cot(90^circ - θ)) + (tan(90^circ - θ))/(cot θ)`
Without using trigonometric tables, find the value of the expression:
sin (50° + θ) – cos (40° – θ) + tan 1° tan 10° tan 20° tan 70° tan 80° tan 89°
Show that `(cos^2(45^circ + θ) + cos^2(45^circ - θ))/(tan(60^circ + θ) tan(30^circ - θ)) = 1`.
R.S. Aggarwal solutions for मैथमैटिक्स [अंग्रेजी] कक्षा १० 12 Trigonometric Ratios of Some Complemantary Angles MULTIPLE-CHOICE QUESTIONS (MCQ) [Pages 593 - 594]
Choose the correct answer in each of the following questions:
`(sec 32^circ)/("cosec" 58^circ)` = ?
`2/3`
`16/29`
`16/3`
1
`(cos 12^circ)/(sin 78^circ) + (tan 23^circ)/(cot 67^circ)` = ?
0
1
2
`3/2`
tan 10° tan 15° tan 75° tan 80° = ?
`sqrt(3)`
1
`1/sqrt(3)`
–1
tan 5° tan 25° tan 30° tan 65° tan 85° = ?
1
`sqrt(3)`
`1/sqrt(3)`
`1/2`
cos 1° cos 2° cos 3°... cos 180° = ?
0
1
–1
`1/2`
sin 43° cos 47° + cos 43° sin 47° = ?
0
1
sin 4°
cos 4°
sec 70° sin 20° + cos 20° cosec 70° = ?
0
1
2
–2
cosec2 57° – tan2 33° = ?
1
0
–1
2
sec2 10° – cot2 80° = ?
0
1
`3/4`
`1/2`
`(2 sin^2 63^circ + 1 + 2 sin^2 27^circ)/(3 cos^2 17^circ - 2 + 3 cos^2 73^circ)` = ?
`2/3`
`3/2`
2
3
sin 38° – cos 52° = ?
0
1
`sqrt(3)/2`
`2/sqrt(3)`
`((sin^2 23^circ + sin^2 67^circ))/((cos^2 13^circ + cos^2 77^circ)) + sin^2 59^circ + cos 59^circ sin 21^circ` = ?
3
2
1
0
`((2 tan^2 30^circ sec^2 52^circ sin^2 38^circ)/("cosec"^2 70^circ - tan^2 20^circ))` = ?
2
1
`2/3`
`3/2`
`((cos 38^circ "cosec" 52^circ)/(tan 18^circ tan 35^circ tan 60^circ tan 72^circ tan 55^circ))` = ?
`1/3`
`1/sqrt(3)`
`sqrt(3)`
`2/sqrt(3)`
sin (60° + θ) – cos (30° – θ) = ?
2 sin θ
2 cos θ
0
1
If A and B are acute angles such that sin A = cos B then (A + B) = ?
30°
45°
60°
90°
If cos (α + β) = 0 then sin (α – β) = ?
sin 2α
cos 2β
sin α
cos β
sin (45° + θ) – cos (45° – θ) = ?
0
1
2
–2
If sec 4A = cosec (A – 10°) and 4A is acute then A = ?
20°
25°
30°
40°
If sin 3A = cos (A – 10°) and 3A is acute then A =?
15°
20°
25°
30°
Fill in the blanks.
cot 34° – tan 56° = .....
cosec 31° – sec 59° = ......
cos267° + cos223° = ......
cosec254° – tan236° = ......
sec240° – cot250° = ......
Solutions for 12: Trigonometric Ratios of Some Complemantary Angles
![R.S. Aggarwal solutions for मैथमैटिक्स [अंग्रेजी] कक्षा १० chapter 12 - Trigonometric Ratios of Some Complemantary Angles R.S. Aggarwal solutions for मैथमैटिक्स [अंग्रेजी] कक्षा १० chapter 12 - Trigonometric Ratios of Some Complemantary Angles - Shaalaa.com](/images/mathematics-english-class-10_6:8f062ea57bdf49abb4f6d22550b39d56.jpg)
R.S. Aggarwal solutions for मैथमैटिक्स [अंग्रेजी] कक्षा १० chapter 12 - Trigonometric Ratios of Some Complemantary Angles
Shaalaa.com has the CBSE, Karnataka Board Mathematics मैथमैटिक्स [अंग्रेजी] कक्षा १० CBSE, Karnataka Board solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. R.S. Aggarwal solutions for Mathematics मैथमैटिक्स [अंग्रेजी] कक्षा १० CBSE, Karnataka Board 12 (Trigonometric Ratios of Some Complemantary Angles) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.
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