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प्रश्न
Without using trigonometric tables, find the value of the expression:
`(sec (90^circ - θ)"cosec" θ - tan (90^circ - θ)cot θ + cos^2 25^circ + cos^2 65^circ)/(3 tan 27^circ tan 63^circ)`
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उत्तर
Step 1: Simplify the numerator terms
The numerator of the expression is:
sec(90° – θ) cosec θ – tan(90° – θ) cot θ + cos2 25 + cos2 65
We can evaluate this in three parts:
1. First term: sec(90° – θ) cosec θ
Using the complementary angle identity sec(90° – θ) = cosec θ:
sec(90° – θ) cosec θ = cosec θ · cosec θ = cosec2 θ
2. Second term: tan(90° – θ) cot θ
Using the complementary angle identity tan(90° – θ) = cot θ:
tan(90° – θ) cot θ = cot θ · cot θ = cot2 θ
Combining these first two parts gives us: cosec2 θ – cot2 θ. From the standard Pythagorean identity, we know that cosec2 θ – cot2 θ = 1.
3. Third part: cos2 25° + cos2 65°
Since 65° and 25° are complementary angles (65° = 90° – 25°), we can apply cos(90° – A) = sin A:
cos 65° = cos(90° – 25°) = sin 25°
cos2 65° = sin2 25°
Substituting this back in gives the identity cos2 25° + sin2 25° = 1.
Total value of the numerator:
Numerator = (cosec2 θ – cot2 θ) + (cot2 25° + cot2 65°)
= 1 + 1
= 2
Step 2: Simplify the denominator term
The denominator of the expression is:
3 tan 27° tan 63°
Since 63° = 90° – 27°, we apply the identity tan(90° – A) = cot A:
tan 63° = tan(90° – 27°) = cot 27°
Since tangent and cotangent are reciprocals, their product is 1 (tan A · cot A = 1):
tan 27° · cot 27° = 1
Total value of the denominator:
Denominator = 3 · 1 = 3
Step 3: Final Division
Now substitute the simplified values of the numerator and the denominator back into the original fraction:
`"Numerator"/"Denominator" = 2/3`
