Question

`(sec 32^circ)/("cosec"  58^circ)` = ?

विकल्प

• `2/3`

• `16/29`

• `16/3`

• 1

Answer 1

1

Explanation:

`(sec 32^circ)/("cosec"  58^circ) = (sec 32^circ)/("cosec" (90^circ - 32^circ))`

= `(sec 32^circ)/(sec 32^circ)`

= 1