Question

`(cos 12^circ)/(sin 78^circ) + (tan 23^circ)/(cot 67^circ)` = ?

विकल्प

• 0

• 1

• 2

• `3/2`

Answer 1

2

Explanation:

`(cos 12^circ)/(sin 78^circ) + (tan 23^circ)/(cot 67^circ) = (cos 12^circ)/(sin(90^circ - 12^circ)) + (tan 23^circ)/(sin(90^circ - 23^circ))`

= `(cos 12^circ)/(cos 12^circ) + (tan 23^circ)/(tan 23^circ)`

= 1 + 1

= 2