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Question
`(cos 12^circ)/(sin 78^circ) + (tan 23^circ)/(cot 67^circ)` = ?
Options
0
1
2
`3/2`
MCQ
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Solution
2
Explanation:
`(cos 12^circ)/(sin 78^circ) + (tan 23^circ)/(cot 67^circ) = (cos 12^circ)/(sin(90^circ - 12^circ)) + (tan 23^circ)/(sin(90^circ - 23^circ))`
= `(cos 12^circ)/(cos 12^circ) + (tan 23^circ)/(tan 23^circ)`
= 1 + 1
= 2
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