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Question
`(sec 32^circ)/("cosec" 58^circ)` = ?
Options
`2/3`
`16/29`
`16/3`
1
MCQ
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Solution
1
Explanation:
`(sec 32^circ)/("cosec" 58^circ) = (sec 32^circ)/("cosec" (90^circ - 32^circ))`
= `(sec 32^circ)/(sec 32^circ)`
= 1
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