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Balbharati solutions for मैथमेटिक्स एण्ड स्टैटिस्टिक्स १ (आर्ट्स एण्ड सायन्स) [अंग्रेजी] कक्षा ११ महाराष्ट्र स्टेट बोर्ड chapter 3 - Trigonometry - 2 [Latest edition]

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Balbharati solutions for मैथमेटिक्स एण्ड स्टैटिस्टिक्स १ (आर्ट्स एण्ड सायन्स) [अंग्रेजी] कक्षा ११ महाराष्ट्र स्टेट बोर्ड chapter 3 - Trigonometry - 2 - Shaalaa.com
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Solutions for Chapter 3: Trigonometry - 2

Below listed, you can find solutions for Chapter 3 of Maharashtra State Board Balbharati for मैथमेटिक्स एण्ड स्टैटिस्टिक्स १ (आर्ट्स एण्ड सायन्स) [अंग्रेजी] कक्षा ११ महाराष्ट्र स्टेट बोर्ड.


Exercise 3.1Exercise 3.2Exercise 3.3Exercise 3.4Exercise 3.5Miscellaneous Exercise 3
Exercise 3.1 [Pages 39 - 40]

Balbharati solutions for मैथमेटिक्स एण्ड स्टैटिस्टिक्स १ (आर्ट्स एण्ड सायन्स) [अंग्रेजी] कक्षा ११ महाराष्ट्र स्टेट बोर्ड 3 Trigonometry - 2 Exercise 3.1 [Pages 39 - 40]

1. (i)Page 39

Find the value of:

sin 15°

1. (ii)Page 39

Find the values of:

cos 75°

1. (iii)Page 39

Find the values of:

tan 105°

1. (iv)Page 39

Find the values of:

cot 225°

2. (i)Page 39

Prove the following:

`cos (pi/2 - x) cos(pi/2 - y) - sin(pi/2 - x) sin(pi/2 - y)` = – cos (x + y)

2. (ii)Page 39

Prove the following:

`tan(pi/4 + theta) = (1 + tan theta)/(1 - tan theta)`

2. (iii)Page 39

Prove the following:

`((1 + tan x)/(1 - tan x))^2 = tan(pi/4 + x)/(tan(pi/4 - x))`

2. (iv)Page 39

Prove the following:

sin [(n + 1)A]. sin [(n + 2)A] + cos [(n + 1)A]. cos [(n + 2)A] = cos A

2. (v)Page 39

Prove the following:

`sqrt(2)cos (pi/4 - "A")` = cos A + sin A

2. (vi)Page 39

Prove the following:

`(cos(x - y))/(cos(x + y)) = (cotx coty + 1)/(cotx coty - 1)`

2. (vii)Page 39

Prove the following:

cos(x + y).cos(x − y) = cos2y − sin2x

2. (viii)Page 39

Prove the following:

`(tan5"A" - tan3"A")/(tan5"A" + tan3"A") = (sin2"A")/(sin8"A")`

2. (ix)Page 39

Prove the following:

tan8θ − tan5θ − tan3θ = tan8θ · tan5θ · tan3θ

2. (x)Page 39

Prove the following:

tan50° = tan40° + 2 tan10°

2. (xi)Page 39

Prove the following:

`(cos27^circ + sin27^circ)/(cos27^circ - sin27^circ)` = tan72°

2. (xii)Page 39

Prove the following:

tan10° + tan35° + tan10°.tan35° = 1

2. (xiii)Page 39

Prove the following:

`(cot"A"cot4"A" + 1)/(cot"A" cot4"A" - 1) = (cos3"A")/(cos5"A")`

2. (xiv)Page 39

Prove the following:

`(cos15^circ - sin15^circ)/(cos15^circ + sin15^circ) = 1/sqrt(3)`

3. (i)Page 40

If sin A = `(-5)/13, pi < "A" < (3pi)/2` and cos B = `3/5, (3pi)/2 < "B" < 2pi` find sin (A + B)

3. (ii)Page 40

If sin A = `(-5)/13, pi < "A" < (3pi)/2` and cos B = `3/5, (3pi)/2 < "B" < 2pi` find cos (A – B)

3. (iii)Page 40

If sin A = `(-5)/13, pi < "A" < (3pi)/2` and cos B = `3/5, (3pi)/2 < "B" < 2pi` find tan (A + B)

4Page 40

If tan A = `5/6, tan "B" = 1/11`, prove that A + B = `pi/4`

Exercise 3.2 [Page 42]

Balbharati solutions for मैथमेटिक्स एण्ड स्टैटिस्टिक्स १ (आर्ट्स एण्ड सायन्स) [अंग्रेजी] कक्षा ११ महाराष्ट्र स्टेट बोर्ड 3 Trigonometry - 2 Exercise 3.2 [Page 42]

1. (i)Page 42

Find the value of sin 690°.

1. (ii)Page 42

Find the value of :

sin (495°)

1. (iii)Page 42

Find the value of :

cos 315°

1. (iv)Page 42

Find the value of :

cos (600°)

1. (v)Page 42

Find the value of :

tan 225°

1. (vi)Page 42

Find the value of :

tan (– 690°)

1. (vii)Page 42

Find the value of :

sec 240°

1. (viii)Page 42

Find the value of:

sec (–855°) 

1. (ix)Page 42

Find the value of :

cosec 780°

1. (x)Page 42

Find the value of :

cot (– 1110°)

2. (i)Page 42

Prove the following:

`(cos(pi + x) cos(-x))/(sin(pi - x)cos(pi/2 + x))` = cot2x

2. (ii)Page 42

Prove the following:

`cos((3pi)/2 + x) cos(2pi + x)[cot((3pi)/2 - x) + cot(2pi + x)]` = 1

2. (iii)Page 42

Prove the following:

sec 840° . cot (– 945°) + sin 600° tan (– 690°) = `3/2`

2. (iv)Page 42

Prove the following:

`("cosec"(90^circ - x)sin(180^circ - x)cot(360^circ - x))/(sec(180^circ + x)tan(90^circ + x)sin(-x))` = 1

2. (v)Page 42

Prove the following:

`(sin^3(pi + x)sec^2(pi - x)tan(2pi - x))/(cos^2(pi/2 + x)sin(pi - x)"cosec"^2 - x)` = tan3x

2. (vi)Page 42

Prove the following:

cosθ + sin (270° + θ) − sin (270° − θ) + cos (180° + θ) = 0

Exercise 3.3 [Page 48]

Balbharati solutions for मैथमेटिक्स एण्ड स्टैटिस्टिक्स १ (आर्ट्स एण्ड सायन्स) [अंग्रेजी] कक्षा ११ महाराष्ट्र स्टेट बोर्ड 3 Trigonometry - 2 Exercise 3.3 [Page 48]

1. (i)Page 48

Find the value of :

`sin  pi/8`

1. (ii)Page 48

Find the value of:

`cos  pi/8`

2Page 48

Find sin 2x, cos 2x, tan 2x if secx = `(-13)/5, pi/2 < x < pi`

3. (i)Page 48

Prove the following:

`(1 - cos2theta)/(1 + cos2theta)` = tan2θ

3. (ii)Page 48

Prove the following:

(sin 3x + sin x)sin x + (cos 3x – cos x) cos x = 0

3. (iii)Page 48

Prove the following:

(cos x + cos y)2 + (sin x – sin y)2 = `4cos^2  ((x + y))/2`

3. (iv)Page 48

Prove the following:

(cos x – cos y)2 + (sin x – sin y)2 = `4sin^2  ((x - y))/2`

3. (v)Page 48

Prove the following:

tan x + cot x = 2 cosec 2x

3. (vi)Page 48

Prove the following:

`(cosx + sinx)/(cosx - sinx) - (cosx - sinx)/(cosx + sinx)` = 2tan2x

3. (vii)Page 48

Prove the following:

`sqrt(2 + sqrt(2 + sqrt(2 + 2cos8x)` = 2 cos x

3. (viii)Page 48

Prove the following:

16 sin θ cos θ cos 2θ cos 4θ cos 8θ = sin 16θ

3. (ix)Page 48

Prove the following:

`(sin3x)/cosx + (cos3x)/sinx` = 2 cot 2x

3. (x)Page 48

Prove the following:

`cosx/(1 + sinx) = (cot(x/2) - 1)/(cot(x/2) + 1)`

3. (xi)Page 48

Prove the following:

`(tan(theta/2) + cot(theta/2))/(cot(theta/2) - tan(theta/2))` = secθ

3. (xii)Page 48

Prove the following:

`1/(tan3"A" - tan"A") - 1/(cot3"A" - cot"A")` = cot2A

3. (xiii)Page 48

Prove the following:

cos7° cos14° cos28° cos56° = `sin68^circ/(16cos83^circ)`

3. (xiv)Page 48

Prove the following:

`(sin^2(-160^circ))/(sin^(2)70^circ) + sin(180^circ - theta)/sintheta` = sec220°

3. (xv)Page 48

Prove the following:

`(2cos 4x + 1)/(2cosx + 1)` = (2 cos x – 1) (2 cos 2x – 1)

3. (xvi)Page 48

Prove the following:

cos2x + cos2(x + 120°) + cos2(x – 120°) = `3/2`

3. (xvii)Page 48

Prove the following:

2cosec 2x + cosec x = `secx cot(x/2)`

3. (xviii)Page 48

Prove the following:

`4 cos x. cos(x + pi/3) . cos (x - pi/3)` = cos 3x

3. (xix)Page 48

Prove the following:

`sinx tan(x/2) + 2cosx = 2/(1 + tan^2(x/2))`

Exercise 3.4 [Page 51]

Balbharati solutions for मैथमेटिक्स एण्ड स्टैटिस्टिक्स १ (आर्ट्स एण्ड सायन्स) [अंग्रेजी] कक्षा ११ महाराष्ट्र स्टेट बोर्ड 3 Trigonometry - 2 Exercise 3.4 [Page 51]

1. (i)Page 51

Express the following as a sum or difference of two trigonometric function:

2 sin 4x cos 2x

1. (ii)Page 51

Express the following as a sum or difference of two trigonometric function:

`2sin  (2pi)/3 cos  pi/2`

1. (iii)Page 51

Express the following as a sum or difference of two trigonometric function:

2 cos 4θ cos 2θ

1. (iv)Page 51

Express the following as a sum or difference of two trigonometric function:

2 cos 35° cos 75°

2. (i)Page 51

Prove the following :

`(sin2x + sin2y)/(sin2x - sin2y) = (tan(x + y))/(tan(x - y))`

2. (ii)Page 51

Prove the following :

sin 6x + sin 4x – sin 2x = 4 cos x sin 2x cos 3x

2. (iii)Page 51

Prove the following :

`(sinx - sin3x + sin5x - sin7x)/(cosx - cos3x - cos5x + cos7x)` = cot2x

2. (iv)Page 51

Prove the following :

sin 18° cos 39° + sin 6° cos 15° = sin 24° cos 33°

2. (v)Page 51

Prove the following :

cos 20° cos 40° cos 60° cos 80° = `1/16`

2. (vi)Page 51

Prove the following :

sin 20° sin 40° sin 60° sin 80° = `3/16`

Exercise 3.5 [Page 54]

Balbharati solutions for मैथमेटिक्स एण्ड स्टैटिस्टिक्स १ (आर्ट्स एण्ड सायन्स) [अंग्रेजी] कक्षा ११ महाराष्ट्र स्टेट बोर्ड 3 Trigonometry - 2 Exercise 3.5 [Page 54]

1Page 54

In ΔABC, A + B + C = π show that 

cos 2A + cos 2B + cos 2C = –1 – 4 cos A cos B cos C

2Page 54

In ΔABC, A + B + C = π show that

sin A + sin B + sin C = `4cos  "A"/2  cos  "B"/2  cos  "C"/2 `

3Page 54

In ΔABC, A + B + C = π show that

cos A + cos B – cos C = `4cos  "A"/2  cos  "B"/2  sin  "C"/2 - 1`

4Page 54

In ΔABC, A + B + C = π show that

sin2A + sin2B − sin2C = 2 sin A sin B cos C

5Page 54

In ΔABC, A + B + C = π show that

`sin^2  "A"/2 + sin^2  "B"/2 - sin^2  "C"/2 = 1 - 2cos  "A"/2  cos  "B"/2 sin  "C"/2`

6Page 54

In ΔABC, A + B + C = π show that

`cot  "A"/2 + cot  "B"/2 + cot  "C"/2 = cot  "A"/2  cot  "B"/2 cot  "C"/2`

7Page 54

In ΔABC, A + B + C = π show that

tan 2A + tan 2B + tan 2C = tan 2A tan 2B tan 2C

8Page 54

In ΔABC, A + B + C = π show that

cos2A +cos2B – cos2C = 1 – 2 sin A sin B cos C

Miscellaneous Exercise 3 [Pages 56 - 58]

Balbharati solutions for मैथमेटिक्स एण्ड स्टैटिस्टिक्स १ (आर्ट्स एण्ड सायन्स) [अंग्रेजी] कक्षा ११ महाराष्ट्र स्टेट बोर्ड 3 Trigonometry - 2 Miscellaneous Exercise 3 [Pages 56 - 58]

I. (1)Page 56

Select the correct option from the given alternatives :

The value of sin(n + 1) A sin (n + 2) A + cos(n + 1) A cos(n + 2) A is equal to

  • sin A 

  • cos A

  • – cos A

  • sin 2A

I. (2)Page 56

Select the correct option from the given alternatives :

If tan A – tan B = x and cot B – cot A = y, then cot (A – B) = _____

  • `1/y - 1/x`

  • `1/x - 1/y`

  • `1/x + 1/y`

  • `(xy)/(x - y)`

I. (3)Page 56

Select the correct option from the given alternatives :

If sin θ = n sin (θ + 2α), then tan (θ + α) is equal to

  • `(1 + n)/(2 - n) tan alpha`

  • `(1 - n)/(1 + n) tan alpha`

  • tan α

  • `(1 + n)/(1 - n) tan alpha`

I. (iv)Page 57

Select the correct option from the given alternatives:

The value of `costheta/(1 + sin theta)` is equal to .....

  • `tan(theta/2 - pi/4)`

  • `tan(-pi/4 - theta/2)`

  • `tan(pi/4 - theta/2)`

  • `tan(pi/4 + theta/2)`

I. (v)Page 57

Select the correct option from the given alternatives :

The value of cos A cos (60° – A) cos (60° + A) is equal to ......

  • `1/2cos3"A"`

  • cos 3A

  • `1/4cos3"A"`

  • 4 cos 3A

I. (vi)Page 57

Select the correct option from the given alternatives:

The value of `sin  pi/14sin  (3pi)/14sin  (5pi)/14sin  (7pi)/14sin  (9pi)/14sin  (11pi)/14sin  (13pi)/14` is ______.

  • `1/16`

  • `1/64`

  • `1/128`

  • `1/256`

I. (vii)Page 57

Select the correct option from the given alternatives :

If α + β + γ = π then the value of sin2α + sin2β – sin2γ is equal to …......

  • 2 sin α 

  • 2 sin α cos β sin γ

  • 2 sin α sin β cos γ

  • 2 sin α sin β sin γ

I. (viii)Page 57

Select the correct option from the given alternatives :

Let 0 < A, B < `pi/2` satisfying the equation 3 sin2A + 2 sin2B = 1 and 3 sin 2A − 2 sin 2B = 0 then A + 2B is equal to ______

  • π

  • `pi/2`

  • `pi/4`

I, (ix)Page 57

Select the correct option from the given alternatives :

In ∆ABC if cot A cot B cot C > 0 then the triangle is _________

  • Acute angled

  • right angled

  • obtuse angled

  • isosceles right angled

I. (x)Page 57

Select the correct option from the given alternatives :

The numerical value of tan 20° tan 80° cot 50° is equal to ______.

  • `sqrt(3)`

  • `1/sqrt(3)`

  • `2sqrt(3)`

  • `1/(2sqrt(3)`

II. (1)Page 57

Prove the following:

tan 20° tan 80° cot 50° = `sqrt(3)`

II. (2)Page 57

Prove the following:

If sin α sin β − cos α cos β + 1 = 0 then prove cot α tan β = −1

II. (3)Page 57

Prove the following:

`cos  (2pi)/15 cos  (4pi)/15cos  (8pi)/15cos  (16pi)/15 = 1/16`

II. (4)Page 57

Prove the following:

`(1 + cos  pi/8)(1 + cos  (3pi)/8)(1 + cos  (5pi)/8)(1 + cos  (7pi)/8) = 1/8`

II. (5)Page 57

Prove the following:

cos 12°+ cos 84° + cos 156° + cos 132° = `-1/2`

II. (6)Page 57

Prove the following:

`cos(pi/4 + x) + cos(pi/4 - x) = sqrt(2)cosx`

II. (7)Page 57

Prove the following:

`(sin5x - 2sin3x + sinx)/(cos5x - cosx)` = tanx

II. (8)Page 57

Prove the following:

sin26x − sin24x = sin2x sin10x

II . (9)Page 57

Prove the following:

cos22x − cos26x = sin4x sin8x

II. (10)Page 57

Prove the following:

cot4x (sin5x + sin3x) = cotx (sin5x − sin3x)

II. (11)Page 57

Prove the following:

`(cos9x - cos5x)/(sin17x - sin3x) = - (sin2x)/(cos10x)`

II. (12)Page 57

Prove the following:

If sin 2A = λsin 2B then prove that `(tan("A" + "B"))/(tan("A" - "B")) = (lambda + 1)/(lambda - 1)`

II. (13)Page 57

Prove the following:

`(2cos2"A" + 1)/(2cos2"A" - 1)` = tan(60° + A) tan(60° − A)

II. (14)Page 57

Prove the following:

tanA + tan(60° + A) + tan(120° + A) = 3 tan 3A

II. (15)Page 57

Prove the following:

3tan610° – 27 tan410° + 33tan210° = 1

II. (16)Page 58

Prove the following:

cosec 48° + cosec 96° + cosec 192° + cosec 384° = 0

II. (17)Page 58

Prove the following:

3(sin x – cos x)4 + 6(sin x + cos x)2 + 4(sin6x + cos6x) = 13

II. (18)Page 58

Prove the following:

tan A + 2 tan 2A + 4 tan 4A + 8 cot 8A = cot A

II. (19)Page 58

Prove the following:

If A + B + C = `(3pi)/2`, then cos 2A + cos 2B + cos 2C = 1 − 4 sin A sin B sin C

II. (20)Page 58

Prove the following:

In any triangle ABC, sin A − cos B = cos C then ∠B = `pi/2`.

II. (21)Page 58

Prove the following:

`tan^3x/(1 + tan^2x) + cot^3x/(1 + cot^2x)` = secx cosecx − 2sinx cosx 

II. (22)Page 58

Prove the following:

sin 20° sin 40° sin 80° = `sqrt(3)/8`

II. (23)Page 58

Prove the following:

sin 18° = `(sqrt(5) - 1)/4`

II. (24)Page 58

Prove the following:

cos 36° = `(sqrt(5) + 1)/4`

II. (25)Page 58

Prove the following:

sin 36° = `(sqrt(10 - 2sqrt(5)))/4`

II. (26)Page 58

Prove the following:

`sin  pi^"c"/8 = 1/2sqrt(2 - sqrt(2))`

II. (27)Page 58

Prove the following:

`tan  pi/8 = sqrt(2) - 1`

II. (28)Page 58

Prove the following:

tan6° tan42° tan66° tan78° = 1

II. (29)Page 58

Prove the following:

sin47° + sin61° − sin11° − sin25° = cos7°

II. (30)Page 58

Prove the following:

`sqrt(3)  "cosec"20^circ - sec20^circ` = 4

II. (31)Page 58

Prove the following:

In ∆ABC, ∠C = `(2pi)/3`, then prove that cos2A + cos2B − cos A cos B = `3/4`

Solutions for 3: Trigonometry - 2

Exercise 3.1Exercise 3.2Exercise 3.3Exercise 3.4Exercise 3.5Miscellaneous Exercise 3
Balbharati solutions for मैथमेटिक्स एण्ड स्टैटिस्टिक्स १ (आर्ट्स एण्ड सायन्स) [अंग्रेजी] कक्षा ११ महाराष्ट्र स्टेट बोर्ड chapter 3 - Trigonometry - 2 - Shaalaa.com

Balbharati solutions for मैथमेटिक्स एण्ड स्टैटिस्टिक्स १ (आर्ट्स एण्ड सायन्स) [अंग्रेजी] कक्षा ११ महाराष्ट्र स्टेट बोर्ड chapter 3 - Trigonometry - 2

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