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Prove the following: cosθ + sin (270° + θ) − sin (270° − θ) + cos (180° + θ) = 0

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प्रश्न

Prove the following:

cosθ + sin (270° + θ) − sin (270° − θ) + cos (180° + θ) = 0

योग
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उत्तर

L.H.S. = cos θ + sin (270° + θ) − sin (270° − θ) +cos (180° + θ)

= cos θ + (− cos θ) − (− cos θ) − cos θ

= cos θ − cos θ + cos θ − cos θ

= 0

= R.H.S.

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अध्याय 3: Trigonometry - 2 - Exercise 3.2 [पृष्ठ ४२]

APPEARS IN

बालभारती Mathematics and Statistics (Arts and Science) Part 1 [English] Standard 11 Maharashtra State Board
अध्याय 3 Trigonometry - 2
Exercise 3.2 | Q 2. (vi) | पृष्ठ ४२

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