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Prove the following: tan3x1+tan2x+cot3x1+cot2x = secx cosecx − 2sinx cosx - Mathematics and Statistics

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प्रश्न

Prove the following:

`tan^3x/(1 + tan^2x) + cot^3x/(1 + cot^2x)` = secx cosecx − 2sinx cosx 

योग
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उत्तर

L.H.S. = `tan^3x/(1 + tan^2x) + cot^3x/(1 + cot^2x)`

= `tan^3x/sec^2x + cot^3x/("cosec"^2x)`

= `sin^3x/cos^3x xx cos^2x + cos^3x/sin^3x xx sin^2x`

= `sin^3x/cosx  + cos^3x/sinx`

= `(sin^4x + cos^4x)/(sinx*cosx)`

= `((sin^2x + cos^2x)^2 - 2sin^2x cos^2x)/(sinx* cosx)`   ...[∵ a2 + b2 = (a + b)2 – 2ab]

= `(1 - 2sin^2x cos^2x)/(sinx*cosx)`

= `1/(sinx* cosx) - (2sin^2xcos^2x)/(sinx*cosx)`

= secx · cosecx – 2sinx · cosx

= R.H.S.

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Trigonometric Functions of Sum and Difference of Angles
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Trigonometry - 2 - Miscellaneous Exercise 3 [पृष्ठ ५८]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 11 Maharashtra State Board
अध्याय 3 Trigonometry - 2
Miscellaneous Exercise 3 | Q II. (21) | पृष्ठ ५८

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