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Prove the following: sin26x − sin24x = sin2x sin10x - Mathematics and Statistics

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प्रश्न

Prove the following:

sin26x − sin24x = sin2x sin10x

योग
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उत्तर

L.H.S. = sin26x − sin24x 

= (sin6x + sin4x) (sin6x – sin4x)

= `2sin((6x + 4x)/2)*cos((6x - 4x)/2) xx 2cos((6x + 4x)/2)*sin((6x - 4x)/2)`

= 2sin5x · cosx × 2cos5x · sinx

= 2sin x cosx × 2sin5x · cos5x

= sin2x · sin10x

= R.H.S.

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Trigonometric Functions of Triple Angle
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Trigonometry - 2 - Miscellaneous Exercise 3 [पृष्ठ ५७]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 11 Maharashtra State Board
अध्याय 3 Trigonometry - 2
Miscellaneous Exercise 3 | Q II. (8) | पृष्ठ ५७

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