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Prove the following: cos22x − cos26x = sin4x sin8x - Mathematics and Statistics

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प्रश्न

Prove the following:

cos22x − cos26x = sin4x sin8x

योग
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उत्तर

L.H.S. = cos22x − cos26x 

= (cos 2x)2 − (cos 6x)2

= (cos 2x + cos 6x) (cos 2x − cos 6x)

= `[2cos((2x + 6x)/2) cos((2x - 6x)/2)]*[2sin((2x + 6x)/2)sin((6x - 2x)/2)]`

= [2 cos 4x cos (− 2x)] [2 sin 4x sin 2x]

= (2 cos 4x cos 2x) (2 sin 4x sin 2x)

= (2 sin 2x cos 2x) (2 sin 4x cos 4x)

= sin 4x sin 8x

= R.H.S.

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Trigonometric Functions of Triple Angle
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Trigonometry - 2 - Miscellaneous Exercise 3 [पृष्ठ ५७]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 11 Maharashtra State Board
अध्याय 3 Trigonometry - 2
Miscellaneous Exercise 3 | Q II . (9) | पृष्ठ ५७

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