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Prove the following: cos2x + cos2(x + 120°) + cos2(x – 120°) = 32 - Mathematics and Statistics

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प्रश्न

Prove the following:

cos2x + cos2(x + 120°) + cos2(x – 120°) = `3/2`

योग
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उत्तर

L.H.S. = cos2x + cos2(x + 120°) + cos2(x – 120°)

= `(1 + cos 2x)/2 + (1 + cos2(x + 120^circ))/2 + (1 + cos2(x - 120^circ))/2` ......`[∵ cos^2θ = (1+cos2θ)/2]`

`=3/2 + 1/2[cos2x + cos(2x + 240^circ)+cos(2x-240°)]`

= `3/2 + 1/2(cos2x + cos2x  cos 240^circ-sin2x sin240°+cos2x cos240°+sin2x sin240°)`

= `3/2+1/2(cos2x+2cos2x cos240°)`

= `3/2 + 1/2[cos 2x +2 cos2x cos(180° + 60°)]`

= `3/2 + 1/2[cos2x + 2cos2x(- cos 60^circ)]`

= `3/2 + 1/2[cos2x - 2cos2x (1/2)]`

= `3/2+1/2(cos2x-cos2x)`

= `3/2+1/2(0)`

= `3/2`

= R.H.S.

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Trigonometric Functions of Triple Angle
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Trigonometry - 2 - Exercise 3.3 [पृष्ठ ४८]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 11 Maharashtra State Board
अध्याय 3 Trigonometry - 2
Exercise 3.3 | Q 3. (xvi) | पृष्ठ ४८

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