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Prove the following: cos(π+x)cos(-x)sin(π-x)cos(π2+x) = cot2x - Mathematics and Statistics

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प्रश्न

Prove the following:

`(cos(pi + x) cos(-x))/(sin(pi - x)cos(pi/2 + x))` = cot2x

योग
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उत्तर

L.H.S. = `(cos(pi + x) cos(-x))/(sin(pi - x)cos(pi/2 + x))`

= `((-cosx)(cosx))/((sinx)(-sinx)`

= `cos^2x/sin^2x`

= cot2x

= R.H.S.

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अध्याय 3: Trigonometry - 2 - Exercise 3.2 [पृष्ठ ४२]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 11 Maharashtra State Board
अध्याय 3 Trigonometry - 2
Exercise 3.2 | Q 2. (i) | पृष्ठ ४२

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