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Prove the following: cosec(90∘-x)sin(180∘-x)cot(360∘-x)sec(180∘+x)tan(90∘+x)sin(-x) = 1

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प्रश्न

Prove the following:

`("cosec"(90^circ - x)sin(180^circ - x)cot(360^circ - x))/(sec(180^circ + x)tan(90^circ + x)sin(-x))` = 1

योग
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उत्तर

L.H.S. = `("cosec"(90^circ - x)sin(180^circ - x)cot(360^circ - x))/(sec(180^circ + x)tan(90^circ + x)sin(-x))`

= `(secx*sinx*(- cotx))/((-secx)*(-cotx)*(- sinx)`

= `(secx*sinx*cotx)/(secx*cotx*sinx)`

= 1

= R.H.S.

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अध्याय 3: Trigonometry - 2 - Exercise 3.2 [पृष्ठ ४२]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 11 Maharashtra State Board
अध्याय 3 Trigonometry - 2
Exercise 3.2 | Q 2. (iv) | पृष्ठ ४२

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