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Prove the following: 16 sin θ cos θ cos 2θ cos 4θ cos 8θ = sin 16θ - Mathematics and Statistics

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प्रश्न

Prove the following:

16 sin θ cos θ cos 2θ cos 4θ cos 8θ = sin 16θ

योग
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उत्तर

L.H.S. = 16 sin θ cos θ cos 2θ cos 4θ cos 8θ

= 8(2sinθ cosθ) cos2θ cos 4θ cos 8θ

= 8sin 2θ cos 2θ cos 4θ cos 8θ

= 4(2sin 2θ cos 2θ) cos 4θ cos 8θ

= 4sin 4θ cos 4θ cos 8θ

= 2(2sin 4θ cos 4θ) cos 8θ

= 2sin 8θ cos 8θ

= sin 16θ

= R.H.S.

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Trigonometric Functions of Triple Angle
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Trigonometry - 2 - Exercise 3.3 [पृष्ठ ४८]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 11 Maharashtra State Board
अध्याय 3 Trigonometry - 2
Exercise 3.3 | Q 3. (viii) | पृष्ठ ४८

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