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Prove the following: sin [(n + 1)A]. sin [(n + 2)A] + cos [(n + 1)A]. cos [(n + 2)A] = cos A

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प्रश्न

Prove the following:

sin [(n + 1)A]. sin [(n + 2)A] + cos [(n + 1)A]. cos [(n + 2)A] = cos A

योग
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उत्तर

L.H.S. = sin [(n + 1)A]. sin [(n + 2)A] + cos [(n + 1)A]. cos [(n + 2)A]

= cos [(n + 2)A]. cos [(n + 1)A] + sin [(n + 2)A]. sin [(n + 1)A]

Let (n + 2)A = a and (n + 1)A = b .......(i)

∴ L.H.S. = cos a. cos b + sin a. sin b

= cos (a − b)

= cos [(n + 2)A − (n + 1)A] .....[From (i)]

= cos [(n + 2 − n − 1)A]

= cos A

= R.H.S.

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अध्याय 3: Trigonometry - 2 - Exercise 3.1 [पृष्ठ ३९]

APPEARS IN

बालभारती Mathematics and Statistics (Arts and Science) Part 1 [English] Standard 11 Maharashtra State Board
अध्याय 3 Trigonometry - 2
Exercise 3.1 | Q 2. (iv) | पृष्ठ ३९

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