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Prove the following: sin [(n + 1)A]. sin [(n + 2)A] + cos [(n + 1)A]. cos [(n + 2)A] = cos A

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Question

Prove the following:

sin [(n + 1)A]. sin [(n + 2)A] + cos [(n + 1)A]. cos [(n + 2)A] = cos A

Sum
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Solution

L.H.S. = sin [(n + 1)A]. sin [(n + 2)A] + cos [(n + 1)A]. cos [(n + 2)A]

= cos [(n + 2)A]. cos [(n + 1)A] + sin [(n + 2)A]. sin [(n + 1)A]

Let (n + 2)A = a and (n + 1)A = b .......(i)

∴ L.H.S. = cos a. cos b + sin a. sin b

= cos (a − b)

= cos [(n + 2)A − (n + 1)A] .....[From (i)]

= cos [(n + 2 − n − 1)A]

= cos A

= R.H.S.

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Chapter 3: Trigonometry - 2 - Exercise 3.1 [Page 39]

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