(English Medium) ICSE Class 10 - CISCE Question Bank Solutions

Solve.
`cos22/sin68`

Solve.
`tan47/cot43`

Solve.
`sec75/(cosec15)`

Solve.
`cos55/sin35+cot35/tan55`

In the figure, given below, AB and CD are two parallel chords and O is the centre. If the radius of the circle is 15 cm, find the distance MN between the two chords of lengths 24 cm and 18 cm respectively.

solve.
cos²40° + cos²50°

solve.
sec² 18° - cot² 72°

Solve.
sin15° cos75° + cos15° sin75°

Solve.
sin42° sin48° - cos42° cos48°

Evaluate.
sin(90° - A) cosA + cos(90° - A) sinA

Evaluate.
sin²35° + sin²55°

Evaluate.
`cot54^@/(tan36^@)+tan20^@/(cot70^@)-2`

Evaluate.
`(2tan53^@)/(cot37^@)-cot80^@/tan10^@`

Evaluate.
cos²25° + cos²65° - tan²45°

Evaluate.
`(cos^2 32^@+cos^2 58^@)/(sin^2 59^@+sin^2 31^@)`

Evaluate.
`(sin77^@/cos13^@)^2+(cos77^@/sin13^@)-2cos^2 45^@`

Evaluate.
`cos^2 26^@+cos65^@sin26^@+tan36^@/cot54^@`

Show that : sin 42° sec 48° + cos 42° cosec 48° = 2

Show that : `sin26^circ/sec64^circ  + cos26^circ/(cosec64^circ) = 1`

Express the following in terms of angle between 0° and 45°:

sin 59° + tan 63°