Advertisements
Advertisements
प्रश्न
Evaluate:
`2(tan35^@/cot55^@)^2 + (cot55^@/tan35^@)^2 - 3(sec40^@/(cosec50^@))`
Advertisements
उत्तर
`2(tan35^@/cot55^@)^2 + (cot55^@/tan35^@)^2 - 3(sec40^@/(cosec50^@))`
= `2(tan(90^@-55^@)/cot55^@)^2 + (cot(90^@-35^@)/tan35^@)^2 - 3(sec(90^@-50^@)/(cosec50^@))`
= `2(cot55^@/cot55^@)^2 + (tan35^@/tan35^@)^2 - 3((cosec50^@)/(cosec50^@))` ...`[∵ tan (90^@ - theta) = cot theta` `cot(90^@ - theta) = tan theta` ` sec(90^@ - theta) = cosec theta`]
= 2 × (1)2 + (1)2 – 3 × 1
= 2 × 1 + 1 – 3
= 2 + 1 – 3
= 0
APPEARS IN
संबंधित प्रश्न
If tan 2θ = cot (θ + 6º), where 2θ and θ + 6º are acute angles, find the value of θ
Prove the following trigonometric identities.
`((1 + cot^2 theta) tan theta)/sec^2 theta = cot theta`
Solve.
`cos22/sin68`
Use tables to find the acute angle θ, if the value of cos θ is 0.6885
Find A, if 0° ≤ A ≤ 90° and sin 3A – 1 = 0
If \[\sec\theta = \frac{13}{12}\], find the values of other trigonometric ratios.
If 5 tan θ − 4 = 0, then the value of \[\frac{5 \sin \theta - 4 \cos \theta}{5 \sin \theta + 4 \cos \theta}\] is:
If 8 tan x = 15, then sin x − cos x is equal to
If \[\cos \theta = \frac{2}{3}\] then 2 sec2 θ + 2 tan2 θ − 7 is equal to
The value of the expression (cos2 23° – sin2 67°) is positive.
