Advertisements
Advertisements
प्रश्न
Use tables to find cosine of 65° 41’
Advertisements
उत्तर
cos 65° 41’ = cos (65° 36’ + 5’)
= 0.4131 − 0.0013
= 0.4118
APPEARS IN
संबंधित प्रश्न
If `cosθ=1/sqrt(2)`, where θ is an acute angle, then find the value of sinθ.
If \[\sec\theta = \frac{13}{12}\], find the values of other trigonometric ratios.
If θ and 2θ − 45° are acute angles such that sin θ = cos (2θ − 45°), then tan θ is equal to
Sin 2A = 2 sin A is true when A =
A triangle ABC is right-angled at B; find the value of `(sec "A". sin "C" - tan "A". tan "C")/sin "B"`.
In the case, given below, find the value of angle A, where 0° ≤ A ≤ 90°.
sin (90° - 3A).cosec 42° = 1.
In the given figure, if AB = 14 cm, BD = 10 cm and DC = 8 cm, then the value of tan B is ______.

If x and y are complementary angles, then ______.
If sec A + tan A = x, then sec A = ______.
`tan 47^circ/cot 43^circ` = 1
