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प्रश्न
Evaluate:
`sin80^circ/(cos10^circ) + sin59^circ sec31^circ`
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उत्तर
`sin80^circ/(cos10^circ) + sin59^circ sec31^circ`
= `sin(90^circ - 10^circ)/(cos10^circ) + sin(90^circ - 31^circ)sec31^circ`
= `cos10^circ/(cos10^circ) + cos31^circ/cos31^circ`
= 1 + 1
= 2
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