Advertisements
Advertisements
प्रश्न
Evaluate:
`sin80^circ/(cos10^circ) + sin59^circ sec31^circ`
Advertisements
उत्तर
`sin80^circ/(cos10^circ) + sin59^circ sec31^circ`
= `sin(90^circ - 10^circ)/(cos10^circ) + sin(90^circ - 31^circ)sec31^circ`
= `cos10^circ/(cos10^circ) + cos31^circ/cos31^circ`
= 1 + 1
= 2
संबंधित प्रश्न
If `tan theta = 1/sqrt2` find the value of `(cosec^2 theta - sec^2 theta)/(cosec^2 theta + cot^2 theta)`
Evaluate:
`(sin35^circ cos55^circ + cos35^circ sin55^circ)/(cosec^2 10^circ - tan^2 80^circ)`
Evaluate:
`sec26^@ sin64^@ + (cosec33^@)/sec57^@`
Evaluate:
cos 40° cosec 50° + sin 50° sec 40°
Find A, if 0° ≤ A ≤ 90° and 2 cos2 A + cos A – 1 = 0
Given
\[\frac{4 \cos \theta - \sin \theta}{2 \cos \theta + \sin \theta}\] what is the value of \[\frac{{cosec}^2 \theta - \sec^2 \theta}{{cosec}^2 \theta + \sec^2 \theta}\]
If tan2 45° − cos2 30° = x sin 45° cos 45°, then x =
If \[\cos \theta = \frac{2}{3}\] then 2 sec2 θ + 2 tan2 θ − 7 is equal to
The value of 3 sin 70° sec 20° + 2 sin 49° sec 51° is
If sec A + tan A = x, then sec A = ______.
