Advertisements
Advertisements
प्रश्न
Use tables to find cosine of 26° 32’
Advertisements
उत्तर
cos 26° 32’ = cos (26° 30’ + 2’)
= 0.8949 − 0.0003
= 0.8946
संबंधित प्रश्न
Express sin 67° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°
Express the following in terms of angles between 0° and 45°:
cosec68° + cot72°
Prove that:
`(sinthetasin(90^circ - theta))/cot(90^circ - theta) = 1 - sin^2theta`
Use tables to find cosine of 65° 41’
Evaluate:
`sec26^@ sin64^@ + (cosec33^@)/sec57^@`
Prove that:
tan (55° - A) - cot (35° + A)
If A and B are complementary angles, prove that:
`(sinA + sinB)/(sinA - sinB) + (cosB - cosA)/(cosB + cosA) = 2/(2sin^2A - 1)`
Find A, if 0° ≤ A ≤ 90° and cos2 A – cos A = 0
If θ is an acute angle such that \[\tan^2 \theta = \frac{8}{7}\] then the value of \[\frac{\left( 1 + \sin \theta \right) \left( 1 - \sin \theta \right)}{\left( 1 + \cos \theta \right) \left( 1 - \cos \theta \right)}\]
If θ is an acute angle such that sec2 θ = 3, then the value of \[\frac{\tan^2 \theta - {cosec}^2 \theta}{\tan^2 \theta + {cosec}^2 \theta}\]
