Advertisements
Advertisements
प्रश्न
Use tables to find cosine of 26° 32’
Advertisements
उत्तर
cos 26° 32’ = cos (26° 30’ + 2’)
= 0.8949 − 0.0003
= 0.8946
APPEARS IN
संबंधित प्रश्न
If tan 2θ = cot (θ + 6º), where 2θ and θ + 6º are acute angles, find the value of θ
Evaluate.
`cot54^@/(tan36^@)+tan20^@/(cot70^@)-2`
If A and B are complementary angles, prove that:
cot B + cos B = sec A cos B (1 + sin B)
If A + B = 90° and \[\tan A = \frac{3}{4}\]\[\tan A = \frac{3}{4}\] what is cot B?
Without using trigonometric tables, prove that:
sec70° sin20° + cos20° cosec70° = 2
Evaluate: `(cos55°)/(sin 35°) + (cot 35°)/(tan 55°)`
Express the following in term of angles between 0° and 45° :
cos 74° + sec 67°
Find the value of the following:
`((cos 47^circ)/(sin 43^circ))^2 + ((sin 72^circ)/(cos 18^circ))^2 - 2cos^2 45^circ`
2(sin6 θ + cos6 θ) – 3(sin4 θ + cos4 θ) is equal to ______.
If x and y are complementary angles, then ______.
