Advertisements
Advertisements
प्रश्न
Use tables to find cosine of 26° 32’
Advertisements
उत्तर
cos 26° 32’ = cos (26° 30’ + 2’)
= 0.8949 − 0.0003
= 0.8946
APPEARS IN
संबंधित प्रश्न
Express sin 67° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°
What is the value of (cos2 67° – sin2 23°)?
Prove that:
`(sinthetasin(90^circ - theta))/cot(90^circ - theta) = 1 - sin^2theta`
Use tables to find sine of 10° 20' + 20° 45'
If A and B are complementary angles, prove that:
`(sinA + sinB)/(sinA - sinB) + (cosB - cosA)/(cosB + cosA) = 2/(2sin^2A - 1)`
Sin 2A = 2 sin A is true when A =
Prove that:
\[\left( \frac{\sin49^\circ}{\cos41^\circ} \right)^2 + \left( \frac{\cos41^\circ}{\sin49^\circ} \right)^2 = 2\]
A, B and C are interior angles of a triangle ABC. Show that
sin `(("B"+"C")/2) = cos "A"/2`
Find the value of the following:
`(cos 70^circ)/(sin 20^circ) + (cos 59^circ)/(sin31^circ) + cos theta/(sin(90^circ - theta))- 8cos^2 60^circ`
If x tan 45° sin 30° = cos 30° tan 30°, then x is equal to ______.
