Advertisements
Advertisements
प्रश्न
Prove that:
`(sinthetasin(90^circ - theta))/cot(90^circ - theta) = 1 - sin^2theta`
Advertisements
उत्तर
L.H.S. = `(sinthetasin(90^@-theta))/cot(90^@-theta)`
= `(sinthetacostheta)/tantheta`
= `(sinthetacostheta)/(sintheta/costheta)`
= cos2θ
= 1 – sin2θ = R.H.S.
संबंधित प्रश्न
Without using trigonometric tables, evaluate the following:
`( i)\frac{\cos37^\text{o}}{\sin53^\text{o}}\text{ }(ii)\frac{\sin41^\text{o}}{\cos 49^\text{o}}(iii)\frac{\sin30^\text{o}17'}{\cos59^\text{o}\43'}`
If A, B, C are the interior angles of a triangle ABC, prove that `\tan \frac{B+C}{2}=\cot \frac{A}{2}`
What is the value of (cos2 67° – sin2 23°)?
Prove the following trigonometric identities.
(cosecθ + sinθ) (cosecθ − sinθ) = cot2 θ + cos2θ
Find the value of x, if cos x = cos 60° cos 30° – sin 60° sin 30°
Use tables to find the acute angle θ, if the value of cos θ is 0.9848
\[\frac{2 \tan 30° }{1 + \tan^2 30°}\] is equal to ______.
In the following figure the value of cos ϕ is
If tan θ = cot 37°, then the value of θ is
If sin A = `3/5`, then show that 4 tan A + 3 sin A = 6 cos A.
